How to get last digits of a number?












3














I have a number such as:



a=875952;


And I want to get last 3 digits of a. I have tried this:



Take[IntegerDigits[a],-3];


I get {9,5,2}
And is there a concise way to get it?






functions







share|improve this question





























    3














    I have a number such as:



    a=875952;


    And I want to get last 3 digits of a. I have tried this:



    Take[IntegerDigits[a],-3];


    I get {9,5,2}
    And is there a concise way to get it?






    functions







    share|improve this question



























      3












      3








      3







      I have a number such as:



      a=875952;


      And I want to get last 3 digits of a. I have tried this:



      Take[IntegerDigits[a],-3];


      I get {9,5,2}
      And is there a concise way to get it?






      functions







      share|improve this question















      I have a number such as:



      a=875952;


      And I want to get last 3 digits of a. I have tried this:



      Take[IntegerDigits[a],-3];


      I get {9,5,2}
      And is there a concise way to get it?






      functions




      functions






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 3 hours ago









      Solomon Ucko

      1033




      1033










      asked 8 hours ago









      user61054

      484




      484






















          2 Answers
          2






          active

          oldest

          votes


















          7














          You can use Part:



          IntegerDigits[a][[-3 ;;]]



          {9, 5, 2}




          Update:




          "Actually I want to see whether a is divisible by 1000"




          Use Divisible:



          Divisible[a, 1000]



          False







          share|improve this answer































            5














            It depends whether you want a three-digit number, in which case try using Mod, as in:



            Mod[a, 1000]


            If you want a List of the digits, then the other solutions above work fine.



            If your goal is instead to see whether a is (evenly) divisible by 1000, then:



            Mod[a,1000] == 0


            yields a True or False.



            Although I don't think this is quite what the OP requests, in response to @TheGreatDuck, here is (inefficient) code that gets the final three digits from any real number:



            a = 3454.983745; 
            
Take[
            
 NestWhile[
            
 If[Last[#] == 0, Drop[#, -1]] &, RealDigits[a][[1]], 
            
  Last[#] == 0 &], -3]





            share|improve this answer























            • Actually I want to see whether a is divisable by 1000, my ways is to judge the last number of a. But it seems complex. Do you have other ways? thanks.
              – user61054
              7 hours ago






            • 6




              A recommendation: Always ask your actual question, rather than an intermediate question. You're more likely to get better answers.
              – David G. Stork
              7 hours ago










            • @DavidG.Stork but what if by last 3 digits we mean last 3 digits of even decimal fractions such as 13.535 returning 535 or the list {5,3,5} or any other equivalent representation? Right now your formula gives the last three whole number place values along with the decimal fraction. (And yes, I can see the askers usage/intention was something very different but it would be interesting to see a more precise answer to the original question.)
              – The Great Duck
              5 hours ago












            • @TheGreatDuck: The OP is rather confused about what is desired: "Actually I want to see whether $a$ is divisable by 1000." I tried to answer his actual question. If the OP wants something different, I'm happy to address that.
              – David G. Stork
              5 hours ago










            • @DavidG.Stork no the op asked a completely different question in the comments. The desired question is what is posted in the question at the top of this page which asks for how "to get last 3 numbers of a". Your first formula does not do that. Any fraction will not return 3 numbers with that formula.
              – The Great Duck
              5 hours ago











            Your Answer





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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            7














            You can use Part:



            IntegerDigits[a][[-3 ;;]]



            {9, 5, 2}




            Update:




            "Actually I want to see whether a is divisible by 1000"




            Use Divisible:



            Divisible[a, 1000]



            False







            share|improve this answer




























              7














              You can use Part:



              IntegerDigits[a][[-3 ;;]]



              {9, 5, 2}




              Update:




              "Actually I want to see whether a is divisible by 1000"




              Use Divisible:



              Divisible[a, 1000]



              False







              share|improve this answer


























                7












                7








                7






                You can use Part:



                IntegerDigits[a][[-3 ;;]]



                {9, 5, 2}




                Update:




                "Actually I want to see whether a is divisible by 1000"




                Use Divisible:



                Divisible[a, 1000]



                False







                share|improve this answer














                You can use Part:



                IntegerDigits[a][[-3 ;;]]



                {9, 5, 2}




                Update:




                "Actually I want to see whether a is divisible by 1000"




                Use Divisible:



                Divisible[a, 1000]



                False








                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited 7 hours ago

























                answered 8 hours ago









                kglr

                176k9198404




                176k9198404























                    5














                    It depends whether you want a three-digit number, in which case try using Mod, as in:



                    Mod[a, 1000]


                    If you want a List of the digits, then the other solutions above work fine.



                    If your goal is instead to see whether a is (evenly) divisible by 1000, then:



                    Mod[a,1000] == 0


                    yields a True or False.



                    Although I don't think this is quite what the OP requests, in response to @TheGreatDuck, here is (inefficient) code that gets the final three digits from any real number:



                    a = 3454.983745; 
                    
Take[
                    
 NestWhile[
                    
 If[Last[#] == 0, Drop[#, -1]] &, RealDigits[a][[1]], 
                    
  Last[#] == 0 &], -3]





                    share|improve this answer























                    • Actually I want to see whether a is divisable by 1000, my ways is to judge the last number of a. But it seems complex. Do you have other ways? thanks.
                      – user61054
                      7 hours ago






                    • 6




                      A recommendation: Always ask your actual question, rather than an intermediate question. You're more likely to get better answers.
                      – David G. Stork
                      7 hours ago










                    • @DavidG.Stork but what if by last 3 digits we mean last 3 digits of even decimal fractions such as 13.535 returning 535 or the list {5,3,5} or any other equivalent representation? Right now your formula gives the last three whole number place values along with the decimal fraction. (And yes, I can see the askers usage/intention was something very different but it would be interesting to see a more precise answer to the original question.)
                      – The Great Duck
                      5 hours ago












                    • @TheGreatDuck: The OP is rather confused about what is desired: "Actually I want to see whether $a$ is divisable by 1000." I tried to answer his actual question. If the OP wants something different, I'm happy to address that.
                      – David G. Stork
                      5 hours ago










                    • @DavidG.Stork no the op asked a completely different question in the comments. The desired question is what is posted in the question at the top of this page which asks for how "to get last 3 numbers of a". Your first formula does not do that. Any fraction will not return 3 numbers with that formula.
                      – The Great Duck
                      5 hours ago
















                    5














                    It depends whether you want a three-digit number, in which case try using Mod, as in:



                    Mod[a, 1000]


                    If you want a List of the digits, then the other solutions above work fine.



                    If your goal is instead to see whether a is (evenly) divisible by 1000, then:



                    Mod[a,1000] == 0


                    yields a True or False.



                    Although I don't think this is quite what the OP requests, in response to @TheGreatDuck, here is (inefficient) code that gets the final three digits from any real number:



                    a = 3454.983745; 
                    
Take[
                    
 NestWhile[
                    
 If[Last[#] == 0, Drop[#, -1]] &, RealDigits[a][[1]], 
                    
  Last[#] == 0 &], -3]





                    share|improve this answer























                    • Actually I want to see whether a is divisable by 1000, my ways is to judge the last number of a. But it seems complex. Do you have other ways? thanks.
                      – user61054
                      7 hours ago






                    • 6




                      A recommendation: Always ask your actual question, rather than an intermediate question. You're more likely to get better answers.
                      – David G. Stork
                      7 hours ago










                    • @DavidG.Stork but what if by last 3 digits we mean last 3 digits of even decimal fractions such as 13.535 returning 535 or the list {5,3,5} or any other equivalent representation? Right now your formula gives the last three whole number place values along with the decimal fraction. (And yes, I can see the askers usage/intention was something very different but it would be interesting to see a more precise answer to the original question.)
                      – The Great Duck
                      5 hours ago












                    • @TheGreatDuck: The OP is rather confused about what is desired: "Actually I want to see whether $a$ is divisable by 1000." I tried to answer his actual question. If the OP wants something different, I'm happy to address that.
                      – David G. Stork
                      5 hours ago










                    • @DavidG.Stork no the op asked a completely different question in the comments. The desired question is what is posted in the question at the top of this page which asks for how "to get last 3 numbers of a". Your first formula does not do that. Any fraction will not return 3 numbers with that formula.
                      – The Great Duck
                      5 hours ago














                    5












                    5








                    5






                    It depends whether you want a three-digit number, in which case try using Mod, as in:



                    Mod[a, 1000]


                    If you want a List of the digits, then the other solutions above work fine.



                    If your goal is instead to see whether a is (evenly) divisible by 1000, then:



                    Mod[a,1000] == 0


                    yields a True or False.



                    Although I don't think this is quite what the OP requests, in response to @TheGreatDuck, here is (inefficient) code that gets the final three digits from any real number:



                    a = 3454.983745; 
                    
Take[
                    
 NestWhile[
                    
 If[Last[#] == 0, Drop[#, -1]] &, RealDigits[a][[1]], 
                    
  Last[#] == 0 &], -3]





                    share|improve this answer














                    It depends whether you want a three-digit number, in which case try using Mod, as in:



                    Mod[a, 1000]


                    If you want a List of the digits, then the other solutions above work fine.



                    If your goal is instead to see whether a is (evenly) divisible by 1000, then:



                    Mod[a,1000] == 0


                    yields a True or False.



                    Although I don't think this is quite what the OP requests, in response to @TheGreatDuck, here is (inefficient) code that gets the final three digits from any real number:



                    a = 3454.983745; 
                    
Take[
                    
 NestWhile[
                    
 If[Last[#] == 0, Drop[#, -1]] &, RealDigits[a][[1]], 
                    
  Last[#] == 0 &], -3]






                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited 4 hours ago

























                    answered 8 hours ago









                    David G. Stork

                    23.1k22051




                    23.1k22051












                    • Actually I want to see whether a is divisable by 1000, my ways is to judge the last number of a. But it seems complex. Do you have other ways? thanks.
                      – user61054
                      7 hours ago






                    • 6




                      A recommendation: Always ask your actual question, rather than an intermediate question. You're more likely to get better answers.
                      – David G. Stork
                      7 hours ago










                    • @DavidG.Stork but what if by last 3 digits we mean last 3 digits of even decimal fractions such as 13.535 returning 535 or the list {5,3,5} or any other equivalent representation? Right now your formula gives the last three whole number place values along with the decimal fraction. (And yes, I can see the askers usage/intention was something very different but it would be interesting to see a more precise answer to the original question.)
                      – The Great Duck
                      5 hours ago












                    • @TheGreatDuck: The OP is rather confused about what is desired: "Actually I want to see whether $a$ is divisable by 1000." I tried to answer his actual question. If the OP wants something different, I'm happy to address that.
                      – David G. Stork
                      5 hours ago










                    • @DavidG.Stork no the op asked a completely different question in the comments. The desired question is what is posted in the question at the top of this page which asks for how "to get last 3 numbers of a". Your first formula does not do that. Any fraction will not return 3 numbers with that formula.
                      – The Great Duck
                      5 hours ago


















                    • Actually I want to see whether a is divisable by 1000, my ways is to judge the last number of a. But it seems complex. Do you have other ways? thanks.
                      – user61054
                      7 hours ago






                    • 6




                      A recommendation: Always ask your actual question, rather than an intermediate question. You're more likely to get better answers.
                      – David G. Stork
                      7 hours ago










                    • @DavidG.Stork but what if by last 3 digits we mean last 3 digits of even decimal fractions such as 13.535 returning 535 or the list {5,3,5} or any other equivalent representation? Right now your formula gives the last three whole number place values along with the decimal fraction. (And yes, I can see the askers usage/intention was something very different but it would be interesting to see a more precise answer to the original question.)
                      – The Great Duck
                      5 hours ago












                    • @TheGreatDuck: The OP is rather confused about what is desired: "Actually I want to see whether $a$ is divisable by 1000." I tried to answer his actual question. If the OP wants something different, I'm happy to address that.
                      – David G. Stork
                      5 hours ago










                    • @DavidG.Stork no the op asked a completely different question in the comments. The desired question is what is posted in the question at the top of this page which asks for how "to get last 3 numbers of a". Your first formula does not do that. Any fraction will not return 3 numbers with that formula.
                      – The Great Duck
                      5 hours ago
















                    Actually I want to see whether a is divisable by 1000, my ways is to judge the last number of a. But it seems complex. Do you have other ways? thanks.
                    – user61054
                    7 hours ago




                    Actually I want to see whether a is divisable by 1000, my ways is to judge the last number of a. But it seems complex. Do you have other ways? thanks.
                    – user61054
                    7 hours ago




                    6




                    6




                    A recommendation: Always ask your actual question, rather than an intermediate question. You're more likely to get better answers.
                    – David G. Stork
                    7 hours ago




                    A recommendation: Always ask your actual question, rather than an intermediate question. You're more likely to get better answers.
                    – David G. Stork
                    7 hours ago












                    @DavidG.Stork but what if by last 3 digits we mean last 3 digits of even decimal fractions such as 13.535 returning 535 or the list {5,3,5} or any other equivalent representation? Right now your formula gives the last three whole number place values along with the decimal fraction. (And yes, I can see the askers usage/intention was something very different but it would be interesting to see a more precise answer to the original question.)
                    – The Great Duck
                    5 hours ago






                    @DavidG.Stork but what if by last 3 digits we mean last 3 digits of even decimal fractions such as 13.535 returning 535 or the list {5,3,5} or any other equivalent representation? Right now your formula gives the last three whole number place values along with the decimal fraction. (And yes, I can see the askers usage/intention was something very different but it would be interesting to see a more precise answer to the original question.)
                    – The Great Duck
                    5 hours ago














                    @TheGreatDuck: The OP is rather confused about what is desired: "Actually I want to see whether $a$ is divisable by 1000." I tried to answer his actual question. If the OP wants something different, I'm happy to address that.
                    – David G. Stork
                    5 hours ago




                    @TheGreatDuck: The OP is rather confused about what is desired: "Actually I want to see whether $a$ is divisable by 1000." I tried to answer his actual question. If the OP wants something different, I'm happy to address that.
                    – David G. Stork
                    5 hours ago












                    @DavidG.Stork no the op asked a completely different question in the comments. The desired question is what is posted in the question at the top of this page which asks for how "to get last 3 numbers of a". Your first formula does not do that. Any fraction will not return 3 numbers with that formula.
                    – The Great Duck
                    5 hours ago




                    @DavidG.Stork no the op asked a completely different question in the comments. The desired question is what is posted in the question at the top of this page which asks for how "to get last 3 numbers of a". Your first formula does not do that. Any fraction will not return 3 numbers with that formula.
                    – The Great Duck
                    5 hours ago


















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