Get the date of the nth day of week in a given year and month












7














Introduction



Often, people refer to dates as the "second Friday in August, 2018" or the "fourth Sunday in March, 2012". But it's hard to tell what date that is! Your task to is to write a program that receives a year, a month, a day of the week, and an integer, and output that date.



Challenge




  • For input, you will get a year, a month, a day of week, and a number.


  • You can take input in any reasonable format, like using a string for the day of week or using a zero indexed weekday, or even take the year and month in a single string. Do explain your input format in your answer, though.


  • The integer that tells you which day of week in the month to target will be an integer from 1-5. The integer will never refer to a day of week that does not exist(e.g. the fifth Friday of February 2019, which doesn't exist).


  • Years will always be positive.


  • Your output can be in any reasonable format, including printing your final date. However, please explain your output format un your answer.


  • Providing the year and month in the output is optional. Also, you may assume the date is valid.



Example Input and Output



Consider this input, with the format being taking in the year as a 4 digit number, month as an integer, day of week as string, and the ordinal number as an integer:




2019, 3, Saturday, 2




Output:




March 9




This is code-golf, so shortest answer wins.










share|improve this question




















  • 1




    I thought I might be able to use GNU date, but amusingly, the parser has an... interesting interpretation here.
    – Doorknob
    2 hours ago
















7














Introduction



Often, people refer to dates as the "second Friday in August, 2018" or the "fourth Sunday in March, 2012". But it's hard to tell what date that is! Your task to is to write a program that receives a year, a month, a day of the week, and an integer, and output that date.



Challenge




  • For input, you will get a year, a month, a day of week, and a number.


  • You can take input in any reasonable format, like using a string for the day of week or using a zero indexed weekday, or even take the year and month in a single string. Do explain your input format in your answer, though.


  • The integer that tells you which day of week in the month to target will be an integer from 1-5. The integer will never refer to a day of week that does not exist(e.g. the fifth Friday of February 2019, which doesn't exist).


  • Years will always be positive.


  • Your output can be in any reasonable format, including printing your final date. However, please explain your output format un your answer.


  • Providing the year and month in the output is optional. Also, you may assume the date is valid.



Example Input and Output



Consider this input, with the format being taking in the year as a 4 digit number, month as an integer, day of week as string, and the ordinal number as an integer:




2019, 3, Saturday, 2




Output:




March 9




This is code-golf, so shortest answer wins.










share|improve this question




















  • 1




    I thought I might be able to use GNU date, but amusingly, the parser has an... interesting interpretation here.
    – Doorknob
    2 hours ago














7












7








7







Introduction



Often, people refer to dates as the "second Friday in August, 2018" or the "fourth Sunday in March, 2012". But it's hard to tell what date that is! Your task to is to write a program that receives a year, a month, a day of the week, and an integer, and output that date.



Challenge




  • For input, you will get a year, a month, a day of week, and a number.


  • You can take input in any reasonable format, like using a string for the day of week or using a zero indexed weekday, or even take the year and month in a single string. Do explain your input format in your answer, though.


  • The integer that tells you which day of week in the month to target will be an integer from 1-5. The integer will never refer to a day of week that does not exist(e.g. the fifth Friday of February 2019, which doesn't exist).


  • Years will always be positive.


  • Your output can be in any reasonable format, including printing your final date. However, please explain your output format un your answer.


  • Providing the year and month in the output is optional. Also, you may assume the date is valid.



Example Input and Output



Consider this input, with the format being taking in the year as a 4 digit number, month as an integer, day of week as string, and the ordinal number as an integer:




2019, 3, Saturday, 2




Output:




March 9




This is code-golf, so shortest answer wins.










share|improve this question















Introduction



Often, people refer to dates as the "second Friday in August, 2018" or the "fourth Sunday in March, 2012". But it's hard to tell what date that is! Your task to is to write a program that receives a year, a month, a day of the week, and an integer, and output that date.



Challenge




  • For input, you will get a year, a month, a day of week, and a number.


  • You can take input in any reasonable format, like using a string for the day of week or using a zero indexed weekday, or even take the year and month in a single string. Do explain your input format in your answer, though.


  • The integer that tells you which day of week in the month to target will be an integer from 1-5. The integer will never refer to a day of week that does not exist(e.g. the fifth Friday of February 2019, which doesn't exist).


  • Years will always be positive.


  • Your output can be in any reasonable format, including printing your final date. However, please explain your output format un your answer.


  • Providing the year and month in the output is optional. Also, you may assume the date is valid.



Example Input and Output



Consider this input, with the format being taking in the year as a 4 digit number, month as an integer, day of week as string, and the ordinal number as an integer:




2019, 3, Saturday, 2




Output:




March 9




This is code-golf, so shortest answer wins.







code-golf date






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 15 mins ago

























asked 2 hours ago









Embodiment of Ignorance

39212




39212








  • 1




    I thought I might be able to use GNU date, but amusingly, the parser has an... interesting interpretation here.
    – Doorknob
    2 hours ago














  • 1




    I thought I might be able to use GNU date, but amusingly, the parser has an... interesting interpretation here.
    – Doorknob
    2 hours ago








1




1




I thought I might be able to use GNU date, but amusingly, the parser has an... interesting interpretation here.
– Doorknob
2 hours ago




I thought I might be able to use GNU date, but amusingly, the parser has an... interesting interpretation here.
– Doorknob
2 hours ago










4 Answers
4






active

oldest

votes


















1















MATL, 28 27 bytes



'1 'ihYO31:q+t8XOi=!A)i)1XO


This uses three inputs:




  • String with month and year: 'March 2019'

  • String with three letters, first capitalized, indicating day of the week: 'Sat'

  • Number: 2.


Output is a string with day, year and month separated with dashes: 09-Mar-2019.



Try it online!



Explanation



Consider inputs 'March 2019', 'Sat', 2.



'1 '    % Push this string
% STACK: '1 '
ih % Input string: month and year. Concatenate
% STACK: '1 March 2019'
YO % Convert to serial date number
% STACK: 737485
31:q+ % Create vector [0 1 2 ... 31] and add element-wise
% STACK: [737485 737486 737487 ... 737515]
t8XO % Duplicate. Convert to date format 'ddd': day of week in three letters. Gives
% a 2D char array
% STACK: [737485 737486 737487 ... 737515], ['Fri'; 'Sat'; 'Sun'; ...; 'Sun']
i= % Input string: day of week in three letters. Compare element-wise with broadcast
% STACK: [737485 737486 737487 ... 737515],
% [0 0 0; 0 0 0; ...; 1 1 1; 0 0 0; ... 1 1 1; ...]
!A % True for rows containing only 1
% STACK: [737485 737486 737487 ... 737515], [0 0 ... 1 ... 0 ... 1 ...]
) % Index: uses the second vector as a mask into the first
% STACK: [737486 737493 737500 737507 737514]
i) % Input number. Index
% STACK: 737493
1XO % Convert to date format 'dd-mmm-yyyy'. Implicit display
% STACK: '09-Mar-2019'





share|improve this answer































    1














    SmileBASIC, 58 bytes



    INPUT M$,D,N
    DTREAD M$+"/01"OUT,,,W?(D-W+7)MOD 7+1+7*(N-1)


    Input is in the form YYYY/MM,weekday,n. The test case would be 2019/03,4,1.



    Ungolfed:



    INPUT YEAR_MONTH$,WEEKDAY,N                  'get input
    DTREAD YEAR_MONTH$+"/01" OUT y,m,d,WEEKDAY_1 'get the day of the week of the first day in the month
    FIRST = (WEEKDAY-WEEKDAY_1+7) MOD 7+1 'get the date of the first <WEEKDAY> in the month
    PRINT FIRST+N*7 'output the date of the <N>th <WEEKDAY> in the month





    share|improve this answer





























      0















      PHP, 46 bytes





      function f($s){return date(d,strtotime($s));};


      Try it online!



      The function receives as input a string like "second saturday of March 2019"



      The function returns the day number.






      share|improve this answer































        0














        JavaScript (ES6), 49 bytes






        f=
        (y,m,d,n)=>(d+6-new Date(y,m,7).getDay())%7+n*7-6

        <div oninput=o.textContent=f(+y.value,+m.value,+d.value,+n.value)>Year: <input id=y type=number value=2019><br>Month: <select id=m><option value=0>Jan<option value=1>Feb<option value=2>Mar<option value=3>Apr<option value=4>May<option value=5>Jun<option value=6>Jul<option value=7>Aug<option value=8>Sep<option value=9>Oct<option value=10>Nov<option value=11>Dec</select><br>Day: <select id=d><option value=0>Sun<option value=1>Mon<option value=2>Tue<option value=3>Wed<option value=4>Thu<option value=5>Fri<option value=6>Sat</select><br>Count: <input id=n type=number value=1 min=1 max=5><pre id=o>





        Month and day of week (starting on Sunday) are zero-indexed.





        share























        • Is the day of week in the format Sunday-Saturday or Monday-Sunday?
          – Embodiment of Ignorance
          4 mins ago










        • @EmbodimentofIgnorance Sorry, I knew I had forgotten something. (The snippet now uses select to make it easier.)
          – Neil
          1 min ago










        • @EmbodimentofIgnorance, Sunday is 0 in JS.
          – Shaggy
          28 secs ago











        Your Answer





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        4 Answers
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        active

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        4 Answers
        4






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        active

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        1















        MATL, 28 27 bytes



        '1 'ihYO31:q+t8XOi=!A)i)1XO


        This uses three inputs:




        • String with month and year: 'March 2019'

        • String with three letters, first capitalized, indicating day of the week: 'Sat'

        • Number: 2.


        Output is a string with day, year and month separated with dashes: 09-Mar-2019.



        Try it online!



        Explanation



        Consider inputs 'March 2019', 'Sat', 2.



        '1 '    % Push this string
        % STACK: '1 '
        ih % Input string: month and year. Concatenate
        % STACK: '1 March 2019'
        YO % Convert to serial date number
        % STACK: 737485
        31:q+ % Create vector [0 1 2 ... 31] and add element-wise
        % STACK: [737485 737486 737487 ... 737515]
        t8XO % Duplicate. Convert to date format 'ddd': day of week in three letters. Gives
        % a 2D char array
        % STACK: [737485 737486 737487 ... 737515], ['Fri'; 'Sat'; 'Sun'; ...; 'Sun']
        i= % Input string: day of week in three letters. Compare element-wise with broadcast
        % STACK: [737485 737486 737487 ... 737515],
        % [0 0 0; 0 0 0; ...; 1 1 1; 0 0 0; ... 1 1 1; ...]
        !A % True for rows containing only 1
        % STACK: [737485 737486 737487 ... 737515], [0 0 ... 1 ... 0 ... 1 ...]
        ) % Index: uses the second vector as a mask into the first
        % STACK: [737486 737493 737500 737507 737514]
        i) % Input number. Index
        % STACK: 737493
        1XO % Convert to date format 'dd-mmm-yyyy'. Implicit display
        % STACK: '09-Mar-2019'





        share|improve this answer




























          1















          MATL, 28 27 bytes



          '1 'ihYO31:q+t8XOi=!A)i)1XO


          This uses three inputs:




          • String with month and year: 'March 2019'

          • String with three letters, first capitalized, indicating day of the week: 'Sat'

          • Number: 2.


          Output is a string with day, year and month separated with dashes: 09-Mar-2019.



          Try it online!



          Explanation



          Consider inputs 'March 2019', 'Sat', 2.



          '1 '    % Push this string
          % STACK: '1 '
          ih % Input string: month and year. Concatenate
          % STACK: '1 March 2019'
          YO % Convert to serial date number
          % STACK: 737485
          31:q+ % Create vector [0 1 2 ... 31] and add element-wise
          % STACK: [737485 737486 737487 ... 737515]
          t8XO % Duplicate. Convert to date format 'ddd': day of week in three letters. Gives
          % a 2D char array
          % STACK: [737485 737486 737487 ... 737515], ['Fri'; 'Sat'; 'Sun'; ...; 'Sun']
          i= % Input string: day of week in three letters. Compare element-wise with broadcast
          % STACK: [737485 737486 737487 ... 737515],
          % [0 0 0; 0 0 0; ...; 1 1 1; 0 0 0; ... 1 1 1; ...]
          !A % True for rows containing only 1
          % STACK: [737485 737486 737487 ... 737515], [0 0 ... 1 ... 0 ... 1 ...]
          ) % Index: uses the second vector as a mask into the first
          % STACK: [737486 737493 737500 737507 737514]
          i) % Input number. Index
          % STACK: 737493
          1XO % Convert to date format 'dd-mmm-yyyy'. Implicit display
          % STACK: '09-Mar-2019'





          share|improve this answer


























            1












            1








            1







            MATL, 28 27 bytes



            '1 'ihYO31:q+t8XOi=!A)i)1XO


            This uses three inputs:




            • String with month and year: 'March 2019'

            • String with three letters, first capitalized, indicating day of the week: 'Sat'

            • Number: 2.


            Output is a string with day, year and month separated with dashes: 09-Mar-2019.



            Try it online!



            Explanation



            Consider inputs 'March 2019', 'Sat', 2.



            '1 '    % Push this string
            % STACK: '1 '
            ih % Input string: month and year. Concatenate
            % STACK: '1 March 2019'
            YO % Convert to serial date number
            % STACK: 737485
            31:q+ % Create vector [0 1 2 ... 31] and add element-wise
            % STACK: [737485 737486 737487 ... 737515]
            t8XO % Duplicate. Convert to date format 'ddd': day of week in three letters. Gives
            % a 2D char array
            % STACK: [737485 737486 737487 ... 737515], ['Fri'; 'Sat'; 'Sun'; ...; 'Sun']
            i= % Input string: day of week in three letters. Compare element-wise with broadcast
            % STACK: [737485 737486 737487 ... 737515],
            % [0 0 0; 0 0 0; ...; 1 1 1; 0 0 0; ... 1 1 1; ...]
            !A % True for rows containing only 1
            % STACK: [737485 737486 737487 ... 737515], [0 0 ... 1 ... 0 ... 1 ...]
            ) % Index: uses the second vector as a mask into the first
            % STACK: [737486 737493 737500 737507 737514]
            i) % Input number. Index
            % STACK: 737493
            1XO % Convert to date format 'dd-mmm-yyyy'. Implicit display
            % STACK: '09-Mar-2019'





            share|improve this answer















            MATL, 28 27 bytes



            '1 'ihYO31:q+t8XOi=!A)i)1XO


            This uses three inputs:




            • String with month and year: 'March 2019'

            • String with three letters, first capitalized, indicating day of the week: 'Sat'

            • Number: 2.


            Output is a string with day, year and month separated with dashes: 09-Mar-2019.



            Try it online!



            Explanation



            Consider inputs 'March 2019', 'Sat', 2.



            '1 '    % Push this string
            % STACK: '1 '
            ih % Input string: month and year. Concatenate
            % STACK: '1 March 2019'
            YO % Convert to serial date number
            % STACK: 737485
            31:q+ % Create vector [0 1 2 ... 31] and add element-wise
            % STACK: [737485 737486 737487 ... 737515]
            t8XO % Duplicate. Convert to date format 'ddd': day of week in three letters. Gives
            % a 2D char array
            % STACK: [737485 737486 737487 ... 737515], ['Fri'; 'Sat'; 'Sun'; ...; 'Sun']
            i= % Input string: day of week in three letters. Compare element-wise with broadcast
            % STACK: [737485 737486 737487 ... 737515],
            % [0 0 0; 0 0 0; ...; 1 1 1; 0 0 0; ... 1 1 1; ...]
            !A % True for rows containing only 1
            % STACK: [737485 737486 737487 ... 737515], [0 0 ... 1 ... 0 ... 1 ...]
            ) % Index: uses the second vector as a mask into the first
            % STACK: [737486 737493 737500 737507 737514]
            i) % Input number. Index
            % STACK: 737493
            1XO % Convert to date format 'dd-mmm-yyyy'. Implicit display
            % STACK: '09-Mar-2019'






            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 33 mins ago

























            answered 52 mins ago









            Luis Mendo

            74k886291




            74k886291























                1














                SmileBASIC, 58 bytes



                INPUT M$,D,N
                DTREAD M$+"/01"OUT,,,W?(D-W+7)MOD 7+1+7*(N-1)


                Input is in the form YYYY/MM,weekday,n. The test case would be 2019/03,4,1.



                Ungolfed:



                INPUT YEAR_MONTH$,WEEKDAY,N                  'get input
                DTREAD YEAR_MONTH$+"/01" OUT y,m,d,WEEKDAY_1 'get the day of the week of the first day in the month
                FIRST = (WEEKDAY-WEEKDAY_1+7) MOD 7+1 'get the date of the first <WEEKDAY> in the month
                PRINT FIRST+N*7 'output the date of the <N>th <WEEKDAY> in the month





                share|improve this answer


























                  1














                  SmileBASIC, 58 bytes



                  INPUT M$,D,N
                  DTREAD M$+"/01"OUT,,,W?(D-W+7)MOD 7+1+7*(N-1)


                  Input is in the form YYYY/MM,weekday,n. The test case would be 2019/03,4,1.



                  Ungolfed:



                  INPUT YEAR_MONTH$,WEEKDAY,N                  'get input
                  DTREAD YEAR_MONTH$+"/01" OUT y,m,d,WEEKDAY_1 'get the day of the week of the first day in the month
                  FIRST = (WEEKDAY-WEEKDAY_1+7) MOD 7+1 'get the date of the first <WEEKDAY> in the month
                  PRINT FIRST+N*7 'output the date of the <N>th <WEEKDAY> in the month





                  share|improve this answer
























                    1












                    1








                    1






                    SmileBASIC, 58 bytes



                    INPUT M$,D,N
                    DTREAD M$+"/01"OUT,,,W?(D-W+7)MOD 7+1+7*(N-1)


                    Input is in the form YYYY/MM,weekday,n. The test case would be 2019/03,4,1.



                    Ungolfed:



                    INPUT YEAR_MONTH$,WEEKDAY,N                  'get input
                    DTREAD YEAR_MONTH$+"/01" OUT y,m,d,WEEKDAY_1 'get the day of the week of the first day in the month
                    FIRST = (WEEKDAY-WEEKDAY_1+7) MOD 7+1 'get the date of the first <WEEKDAY> in the month
                    PRINT FIRST+N*7 'output the date of the <N>th <WEEKDAY> in the month





                    share|improve this answer












                    SmileBASIC, 58 bytes



                    INPUT M$,D,N
                    DTREAD M$+"/01"OUT,,,W?(D-W+7)MOD 7+1+7*(N-1)


                    Input is in the form YYYY/MM,weekday,n. The test case would be 2019/03,4,1.



                    Ungolfed:



                    INPUT YEAR_MONTH$,WEEKDAY,N                  'get input
                    DTREAD YEAR_MONTH$+"/01" OUT y,m,d,WEEKDAY_1 'get the day of the week of the first day in the month
                    FIRST = (WEEKDAY-WEEKDAY_1+7) MOD 7+1 'get the date of the first <WEEKDAY> in the month
                    PRINT FIRST+N*7 'output the date of the <N>th <WEEKDAY> in the month






                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered 15 mins ago









                    12Me21

                    5,44711236




                    5,44711236























                        0















                        PHP, 46 bytes





                        function f($s){return date(d,strtotime($s));};


                        Try it online!



                        The function receives as input a string like "second saturday of March 2019"



                        The function returns the day number.






                        share|improve this answer




























                          0















                          PHP, 46 bytes





                          function f($s){return date(d,strtotime($s));};


                          Try it online!



                          The function receives as input a string like "second saturday of March 2019"



                          The function returns the day number.






                          share|improve this answer


























                            0












                            0








                            0







                            PHP, 46 bytes





                            function f($s){return date(d,strtotime($s));};


                            Try it online!



                            The function receives as input a string like "second saturday of March 2019"



                            The function returns the day number.






                            share|improve this answer















                            PHP, 46 bytes





                            function f($s){return date(d,strtotime($s));};


                            Try it online!



                            The function receives as input a string like "second saturday of March 2019"



                            The function returns the day number.







                            share|improve this answer














                            share|improve this answer



                            share|improve this answer








                            edited 1 hour ago

























                            answered 1 hour ago









                            Кирилл Малышев

                            40115




                            40115























                                0














                                JavaScript (ES6), 49 bytes






                                f=
                                (y,m,d,n)=>(d+6-new Date(y,m,7).getDay())%7+n*7-6

                                <div oninput=o.textContent=f(+y.value,+m.value,+d.value,+n.value)>Year: <input id=y type=number value=2019><br>Month: <select id=m><option value=0>Jan<option value=1>Feb<option value=2>Mar<option value=3>Apr<option value=4>May<option value=5>Jun<option value=6>Jul<option value=7>Aug<option value=8>Sep<option value=9>Oct<option value=10>Nov<option value=11>Dec</select><br>Day: <select id=d><option value=0>Sun<option value=1>Mon<option value=2>Tue<option value=3>Wed<option value=4>Thu<option value=5>Fri<option value=6>Sat</select><br>Count: <input id=n type=number value=1 min=1 max=5><pre id=o>





                                Month and day of week (starting on Sunday) are zero-indexed.





                                share























                                • Is the day of week in the format Sunday-Saturday or Monday-Sunday?
                                  – Embodiment of Ignorance
                                  4 mins ago










                                • @EmbodimentofIgnorance Sorry, I knew I had forgotten something. (The snippet now uses select to make it easier.)
                                  – Neil
                                  1 min ago










                                • @EmbodimentofIgnorance, Sunday is 0 in JS.
                                  – Shaggy
                                  28 secs ago
















                                0














                                JavaScript (ES6), 49 bytes






                                f=
                                (y,m,d,n)=>(d+6-new Date(y,m,7).getDay())%7+n*7-6

                                <div oninput=o.textContent=f(+y.value,+m.value,+d.value,+n.value)>Year: <input id=y type=number value=2019><br>Month: <select id=m><option value=0>Jan<option value=1>Feb<option value=2>Mar<option value=3>Apr<option value=4>May<option value=5>Jun<option value=6>Jul<option value=7>Aug<option value=8>Sep<option value=9>Oct<option value=10>Nov<option value=11>Dec</select><br>Day: <select id=d><option value=0>Sun<option value=1>Mon<option value=2>Tue<option value=3>Wed<option value=4>Thu<option value=5>Fri<option value=6>Sat</select><br>Count: <input id=n type=number value=1 min=1 max=5><pre id=o>





                                Month and day of week (starting on Sunday) are zero-indexed.





                                share























                                • Is the day of week in the format Sunday-Saturday or Monday-Sunday?
                                  – Embodiment of Ignorance
                                  4 mins ago










                                • @EmbodimentofIgnorance Sorry, I knew I had forgotten something. (The snippet now uses select to make it easier.)
                                  – Neil
                                  1 min ago










                                • @EmbodimentofIgnorance, Sunday is 0 in JS.
                                  – Shaggy
                                  28 secs ago














                                0












                                0








                                0






                                JavaScript (ES6), 49 bytes






                                f=
                                (y,m,d,n)=>(d+6-new Date(y,m,7).getDay())%7+n*7-6

                                <div oninput=o.textContent=f(+y.value,+m.value,+d.value,+n.value)>Year: <input id=y type=number value=2019><br>Month: <select id=m><option value=0>Jan<option value=1>Feb<option value=2>Mar<option value=3>Apr<option value=4>May<option value=5>Jun<option value=6>Jul<option value=7>Aug<option value=8>Sep<option value=9>Oct<option value=10>Nov<option value=11>Dec</select><br>Day: <select id=d><option value=0>Sun<option value=1>Mon<option value=2>Tue<option value=3>Wed<option value=4>Thu<option value=5>Fri<option value=6>Sat</select><br>Count: <input id=n type=number value=1 min=1 max=5><pre id=o>





                                Month and day of week (starting on Sunday) are zero-indexed.





                                share














                                JavaScript (ES6), 49 bytes






                                f=
                                (y,m,d,n)=>(d+6-new Date(y,m,7).getDay())%7+n*7-6

                                <div oninput=o.textContent=f(+y.value,+m.value,+d.value,+n.value)>Year: <input id=y type=number value=2019><br>Month: <select id=m><option value=0>Jan<option value=1>Feb<option value=2>Mar<option value=3>Apr<option value=4>May<option value=5>Jun<option value=6>Jul<option value=7>Aug<option value=8>Sep<option value=9>Oct<option value=10>Nov<option value=11>Dec</select><br>Day: <select id=d><option value=0>Sun<option value=1>Mon<option value=2>Tue<option value=3>Wed<option value=4>Thu<option value=5>Fri<option value=6>Sat</select><br>Count: <input id=n type=number value=1 min=1 max=5><pre id=o>





                                Month and day of week (starting on Sunday) are zero-indexed.






                                f=
                                (y,m,d,n)=>(d+6-new Date(y,m,7).getDay())%7+n*7-6

                                <div oninput=o.textContent=f(+y.value,+m.value,+d.value,+n.value)>Year: <input id=y type=number value=2019><br>Month: <select id=m><option value=0>Jan<option value=1>Feb<option value=2>Mar<option value=3>Apr<option value=4>May<option value=5>Jun<option value=6>Jul<option value=7>Aug<option value=8>Sep<option value=9>Oct<option value=10>Nov<option value=11>Dec</select><br>Day: <select id=d><option value=0>Sun<option value=1>Mon<option value=2>Tue<option value=3>Wed<option value=4>Thu<option value=5>Fri<option value=6>Sat</select><br>Count: <input id=n type=number value=1 min=1 max=5><pre id=o>





                                f=
                                (y,m,d,n)=>(d+6-new Date(y,m,7).getDay())%7+n*7-6

                                <div oninput=o.textContent=f(+y.value,+m.value,+d.value,+n.value)>Year: <input id=y type=number value=2019><br>Month: <select id=m><option value=0>Jan<option value=1>Feb<option value=2>Mar<option value=3>Apr<option value=4>May<option value=5>Jun<option value=6>Jul<option value=7>Aug<option value=8>Sep<option value=9>Oct<option value=10>Nov<option value=11>Dec</select><br>Day: <select id=d><option value=0>Sun<option value=1>Mon<option value=2>Tue<option value=3>Wed<option value=4>Thu<option value=5>Fri<option value=6>Sat</select><br>Count: <input id=n type=number value=1 min=1 max=5><pre id=o>





                                share













                                share


                                share








                                edited 2 mins ago

























                                answered 5 mins ago









                                Neil

                                79.4k744177




                                79.4k744177












                                • Is the day of week in the format Sunday-Saturday or Monday-Sunday?
                                  – Embodiment of Ignorance
                                  4 mins ago










                                • @EmbodimentofIgnorance Sorry, I knew I had forgotten something. (The snippet now uses select to make it easier.)
                                  – Neil
                                  1 min ago










                                • @EmbodimentofIgnorance, Sunday is 0 in JS.
                                  – Shaggy
                                  28 secs ago


















                                • Is the day of week in the format Sunday-Saturday or Monday-Sunday?
                                  – Embodiment of Ignorance
                                  4 mins ago










                                • @EmbodimentofIgnorance Sorry, I knew I had forgotten something. (The snippet now uses select to make it easier.)
                                  – Neil
                                  1 min ago










                                • @EmbodimentofIgnorance, Sunday is 0 in JS.
                                  – Shaggy
                                  28 secs ago
















                                Is the day of week in the format Sunday-Saturday or Monday-Sunday?
                                – Embodiment of Ignorance
                                4 mins ago




                                Is the day of week in the format Sunday-Saturday or Monday-Sunday?
                                – Embodiment of Ignorance
                                4 mins ago












                                @EmbodimentofIgnorance Sorry, I knew I had forgotten something. (The snippet now uses select to make it easier.)
                                – Neil
                                1 min ago




                                @EmbodimentofIgnorance Sorry, I knew I had forgotten something. (The snippet now uses select to make it easier.)
                                – Neil
                                1 min ago












                                @EmbodimentofIgnorance, Sunday is 0 in JS.
                                – Shaggy
                                28 secs ago




                                @EmbodimentofIgnorance, Sunday is 0 in JS.
                                – Shaggy
                                28 secs ago


















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