How to find a smallest value in a list?












2














I have a list of point2d coordinate {x,y}. I would like to find the point where x is the smallest. How can I do it in Mathematica?






list-manipulation







share|improve this question


















  • 3




    point2d[[Ordering[point2d, 1][[1]]]]
    – Henrik Schumacher
    11 hours ago






  • 4




    Take a look at MinimalBy
    – Kuba♦
    11 hours ago






  • 2




    First@Sort@point2d
    – Okkes Dulgerci
    10 hours ago
















2














I have a list of point2d coordinate {x,y}. I would like to find the point where x is the smallest. How can I do it in Mathematica?






list-manipulation







share|improve this question


















  • 3




    point2d[[Ordering[point2d, 1][[1]]]]
    – Henrik Schumacher
    11 hours ago






  • 4




    Take a look at MinimalBy
    – Kuba♦
    11 hours ago






  • 2




    First@Sort@point2d
    – Okkes Dulgerci
    10 hours ago














2












2








2


2





I have a list of point2d coordinate {x,y}. I would like to find the point where x is the smallest. How can I do it in Mathematica?






list-manipulation







share|improve this question













I have a list of point2d coordinate {x,y}. I would like to find the point where x is the smallest. How can I do it in Mathematica?






list-manipulation




list-manipulation






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked 11 hours ago









N.T.C

28517




28517








  • 3




    point2d[[Ordering[point2d, 1][[1]]]]
    – Henrik Schumacher
    11 hours ago






  • 4




    Take a look at MinimalBy
    – Kuba♦
    11 hours ago






  • 2




    First@Sort@point2d
    – Okkes Dulgerci
    10 hours ago














  • 3




    point2d[[Ordering[point2d, 1][[1]]]]
    – Henrik Schumacher
    11 hours ago






  • 4




    Take a look at MinimalBy
    – Kuba♦
    11 hours ago






  • 2




    First@Sort@point2d
    – Okkes Dulgerci
    10 hours ago








3




3




point2d[[Ordering[point2d, 1][[1]]]]
– Henrik Schumacher
11 hours ago




point2d[[Ordering[point2d, 1][[1]]]]
– Henrik Schumacher
11 hours ago




4




4




Take a look at MinimalBy
– Kuba♦
11 hours ago




Take a look at MinimalBy
– Kuba♦
11 hours ago




2




2




First@Sort@point2d
– Okkes Dulgerci
10 hours ago




First@Sort@point2d
– Okkes Dulgerci
10 hours ago










1 Answer
1






active

oldest

votes


















6














Initializing some test data:



pts = RandomReal[100, {10, 2}];


Kuba's suggestion in the comments is this:



MinimalBy[pts, First]



{{31.2859, 50.9165}}




and here is a piece of code that captures the idea of Henrik's suggestion:



First@SortBy[pts, First]



{31.2859, 50.9165}




In other programming languages, we might have written a for loop and made a variable keep track of the smallest x coordinate so far. In Mathematica, we can also use loops but we try to stay away from it. If we were to implement that kind of solution in Mathematica, it would look like this instead:



min[pt1_, pt2_] := If[First[pt1] < First[pt2], pt1, pt2]

Fold[min, pts]



{31.2859, 50.9165}




Another pattern that one can see sometimes is to get the smallest value, get the position of the smallest value, and then extract that position from the original list:



minVal = pts[[All, 1]] // Min;

pos = Position[pts, {minVal, _}];

Extract[pts, pos]



{{31.2859, 50.9165}}




Note that I use Extract instead of Part to get the element, it's useful to remember that Extract works well with the type of output that Position gives. We could not have used Part to extract this information without first transforming the expression that Position gave.



I recommend the simplest approaches, i.e. one of the first two presented above. Most of all I recommend MinimalBy.






share|improve this answer























    Your Answer





    StackExchange.ifUsing("editor", function () {
    return StackExchange.using("mathjaxEditing", function () {
    StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
    StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
    });
    });
    }, "mathjax-editing");

    StackExchange.ready(function() {
    var channelOptions = {
    tags: "".split(" "),
    id: "387"
    };
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function() {
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled) {
    StackExchange.using("snippets", function() {
    createEditor();
    });
    }
    else {
    createEditor();
    }
    });

    function createEditor() {
    StackExchange.prepareEditor({
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: false,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: null,
    bindNavPrevention: true,
    postfix: "",
    imageUploader: {
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    },
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    });


    }
    });














    draft saved

    draft discarded


















    StackExchange.ready(
    function () {
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f188640%2fhow-to-find-a-smallest-value-in-a-list%23new-answer', 'question_page');
    }
    );

    Post as a guest















    Required, but never shown

























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    6














    Initializing some test data:



    pts = RandomReal[100, {10, 2}];


    Kuba's suggestion in the comments is this:



    MinimalBy[pts, First]



    {{31.2859, 50.9165}}




    and here is a piece of code that captures the idea of Henrik's suggestion:



    First@SortBy[pts, First]



    {31.2859, 50.9165}




    In other programming languages, we might have written a for loop and made a variable keep track of the smallest x coordinate so far. In Mathematica, we can also use loops but we try to stay away from it. If we were to implement that kind of solution in Mathematica, it would look like this instead:



    min[pt1_, pt2_] := If[First[pt1] < First[pt2], pt1, pt2]
    
Fold[min, pts]



    {31.2859, 50.9165}




    Another pattern that one can see sometimes is to get the smallest value, get the position of the smallest value, and then extract that position from the original list:



    minVal = pts[[All, 1]] // Min;
    
pos = Position[pts, {minVal, _}];
    
Extract[pts, pos]



    {{31.2859, 50.9165}}




    Note that I use Extract instead of Part to get the element, it's useful to remember that Extract works well with the type of output that Position gives. We could not have used Part to extract this information without first transforming the expression that Position gave.



    I recommend the simplest approaches, i.e. one of the first two presented above. Most of all I recommend MinimalBy.






    share|improve this answer




























      6














      Initializing some test data:



      pts = RandomReal[100, {10, 2}];


      Kuba's suggestion in the comments is this:



      MinimalBy[pts, First]



      {{31.2859, 50.9165}}




      and here is a piece of code that captures the idea of Henrik's suggestion:



      First@SortBy[pts, First]



      {31.2859, 50.9165}




      In other programming languages, we might have written a for loop and made a variable keep track of the smallest x coordinate so far. In Mathematica, we can also use loops but we try to stay away from it. If we were to implement that kind of solution in Mathematica, it would look like this instead:



      min[pt1_, pt2_] := If[First[pt1] < First[pt2], pt1, pt2]
      
Fold[min, pts]



      {31.2859, 50.9165}




      Another pattern that one can see sometimes is to get the smallest value, get the position of the smallest value, and then extract that position from the original list:



      minVal = pts[[All, 1]] // Min;
      
pos = Position[pts, {minVal, _}];
      
Extract[pts, pos]



      {{31.2859, 50.9165}}




      Note that I use Extract instead of Part to get the element, it's useful to remember that Extract works well with the type of output that Position gives. We could not have used Part to extract this information without first transforming the expression that Position gave.



      I recommend the simplest approaches, i.e. one of the first two presented above. Most of all I recommend MinimalBy.






      share|improve this answer


























        6












        6








        6






        Initializing some test data:



        pts = RandomReal[100, {10, 2}];


        Kuba's suggestion in the comments is this:



        MinimalBy[pts, First]



        {{31.2859, 50.9165}}




        and here is a piece of code that captures the idea of Henrik's suggestion:



        First@SortBy[pts, First]



        {31.2859, 50.9165}




        In other programming languages, we might have written a for loop and made a variable keep track of the smallest x coordinate so far. In Mathematica, we can also use loops but we try to stay away from it. If we were to implement that kind of solution in Mathematica, it would look like this instead:



        min[pt1_, pt2_] := If[First[pt1] < First[pt2], pt1, pt2]
        
Fold[min, pts]



        {31.2859, 50.9165}




        Another pattern that one can see sometimes is to get the smallest value, get the position of the smallest value, and then extract that position from the original list:



        minVal = pts[[All, 1]] // Min;
        
pos = Position[pts, {minVal, _}];
        
Extract[pts, pos]



        {{31.2859, 50.9165}}




        Note that I use Extract instead of Part to get the element, it's useful to remember that Extract works well with the type of output that Position gives. We could not have used Part to extract this information without first transforming the expression that Position gave.



        I recommend the simplest approaches, i.e. one of the first two presented above. Most of all I recommend MinimalBy.






        share|improve this answer














        Initializing some test data:



        pts = RandomReal[100, {10, 2}];


        Kuba's suggestion in the comments is this:



        MinimalBy[pts, First]



        {{31.2859, 50.9165}}




        and here is a piece of code that captures the idea of Henrik's suggestion:



        First@SortBy[pts, First]



        {31.2859, 50.9165}




        In other programming languages, we might have written a for loop and made a variable keep track of the smallest x coordinate so far. In Mathematica, we can also use loops but we try to stay away from it. If we were to implement that kind of solution in Mathematica, it would look like this instead:



        min[pt1_, pt2_] := If[First[pt1] < First[pt2], pt1, pt2]
        
Fold[min, pts]



        {31.2859, 50.9165}




        Another pattern that one can see sometimes is to get the smallest value, get the position of the smallest value, and then extract that position from the original list:



        minVal = pts[[All, 1]] // Min;
        
pos = Position[pts, {minVal, _}];
        
Extract[pts, pos]



        {{31.2859, 50.9165}}




        Note that I use Extract instead of Part to get the element, it's useful to remember that Extract works well with the type of output that Position gives. We could not have used Part to extract this information without first transforming the expression that Position gave.



        I recommend the simplest approaches, i.e. one of the first two presented above. Most of all I recommend MinimalBy.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited 10 hours ago

























        answered 10 hours ago









        C. E.

        49.8k396201




        49.8k396201






























            draft saved

            draft discarded




















































            Thanks for contributing an answer to Mathematica Stack Exchange!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid …



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            Use MathJax to format equations. MathJax reference.


            To learn more, see our tips on writing great answers.





            Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


            Please pay close attention to the following guidance:


            • Please be sure to answer the question. Provide details and share your research!

            But avoid …



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f188640%2fhow-to-find-a-smallest-value-in-a-list%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            -

            Popular posts from this blog

            Eastern Orthodox Church

            Image
            Not to be confused with Oriental Orthodoxy, Eastern Christianity, or Eastern Catholic Churches. "Eastern Orthodoxy", "Orthodox Church", "Orthodox Catholic Church", and "Orthodox Christian Church" redirect here. For other uses, see Orthodox (disambiguation). This article may be too long to read and navigate comfortably . The readable prose size is 132 kilobytes. Please consider splitting content into sub-articles, condensing it, or adding or removing subheadings. ( January 2018 ) Part of a series on the Eastern Orthodox Church Mosaic of Christ Pantocrator, Hagia Sophia Overview Structure Theology (History of theology) Liturgy Church history Holy Mysteries View of salvation View of Mary View of icons Background Crucifixion / Resurrection / Ascension of Jesus Christianity Christian Church Apostolic succession Four Marks of the Church Orthodoxy Organization Autocephaly Patriarchate ...
            Read more

            Zagreb

            Image
            This article is about the Croatian capital city. For other uses, see Zagreb (disambiguation). City in City of Zagreb, Croatia Zagreb City Grad Zagreb City of Zagreb Clockwise, from top: St. Mark's Square, Croatian State Archives, Zagreb Tram, Art Pavilion, Cibona & HOTO towers and Croatian National Theatre. Flag Coat of arms Zagreb Location of Zagreb in Croatia Show map of Croatia Zagreb Zagreb (Europe) Show map of Europe Coordinates: 45°49′N 15°59′E  /  45.817°N 15.983°E  / 45.817; 15.983 Coordinates: 45°49′N 15°59′E  /  45.817°N 15.983°E  / 45.817; 15.983 Country   Croatia County City of Zagreb RC diocese 1094 Free royal city 1242 Unified 1850 Subdivisions 17 city districts 218 local committees (70 settlements) Government  • Type Mayor-Council  • Mayor Milan Bandić (BM 365)  • City Assembly 51 members BM 365, ZL, NS-R (14) SDP, GLAS, HNS, HSS, NH-PS (13) ...
            Read more

            Understanding the information contained in the Deep Space Network XML data?

            Image
            up vote 1 down vote favorite NASA's Deep Space Network activity can be viewed conveniently at https://eyes.nasa.gov/dsn/dsn.html but if you would like data in a more raw XML form, it can be accessed as described in this answer Below is a small Python script that reads the XML into a list of dictionaries, and saves it to disk as a JSON. The dictionaries are organized at the higher level by dish, then by spacecraft per dish. Question: What are the most-likely meanings of all the data field contained in the Deep Space Network XML data? This is the example url from the other answer, used in the script below: https://eyes.nasa.gov/dsn/data/1365107113.xml def dictify(r,root=True): # https://stackoverflow.com/questions/2148119/how-to-convert-an-xml-string-to-a-dictionary-in-python/30923963#30923963 if root: ret...
            Read more