What is P(A/B) in Venn diagram?












1














enter image description here



I am trying to understand P(A/B) in practice. I know that (A,B) is the intersection between A and B on the diagram, and I know as well that P(A/B) is probability of A given B. But where is P(A/B) on the diagram ?






probability conditional-probability







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New contributor




Mehdi Souregi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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  • 1




    It is not on the diagram.
    – Xi'an
    17 mins ago










  • How can I represent it (on my mind) ?
    – Mehdi Souregi
    15 mins ago










  • Is it a part of (A,B) or part of A, I am confused
    – Mehdi Souregi
    13 mins ago
















1














enter image description here



I am trying to understand P(A/B) in practice. I know that (A,B) is the intersection between A and B on the diagram, and I know as well that P(A/B) is probability of A given B. But where is P(A/B) on the diagram ?






probability conditional-probability







share|cite|improve this question







New contributor




Mehdi Souregi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
















  • 1




    It is not on the diagram.
    – Xi'an
    17 mins ago










  • How can I represent it (on my mind) ?
    – Mehdi Souregi
    15 mins ago










  • Is it a part of (A,B) or part of A, I am confused
    – Mehdi Souregi
    13 mins ago














1












1








1







enter image description here



I am trying to understand P(A/B) in practice. I know that (A,B) is the intersection between A and B on the diagram, and I know as well that P(A/B) is probability of A given B. But where is P(A/B) on the diagram ?






probability conditional-probability







share|cite|improve this question







New contributor




Mehdi Souregi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











enter image description here



I am trying to understand P(A/B) in practice. I know that (A,B) is the intersection between A and B on the diagram, and I know as well that P(A/B) is probability of A given B. But where is P(A/B) on the diagram ?






probability conditional-probability




probability conditional-probability






share|cite|improve this question







New contributor




Mehdi Souregi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|cite|improve this question







New contributor




Mehdi Souregi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|cite|improve this question




share|cite|improve this question






New contributor




Mehdi Souregi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 18 mins ago









Mehdi Souregi

1063




1063




New contributor




Mehdi Souregi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Mehdi Souregi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Mehdi Souregi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








  • 1




    It is not on the diagram.
    – Xi'an
    17 mins ago










  • How can I represent it (on my mind) ?
    – Mehdi Souregi
    15 mins ago










  • Is it a part of (A,B) or part of A, I am confused
    – Mehdi Souregi
    13 mins ago














  • 1




    It is not on the diagram.
    – Xi'an
    17 mins ago










  • How can I represent it (on my mind) ?
    – Mehdi Souregi
    15 mins ago










  • Is it a part of (A,B) or part of A, I am confused
    – Mehdi Souregi
    13 mins ago








1




1




It is not on the diagram.
– Xi'an
17 mins ago




It is not on the diagram.
– Xi'an
17 mins ago












How can I represent it (on my mind) ?
– Mehdi Souregi
15 mins ago




How can I represent it (on my mind) ?
– Mehdi Souregi
15 mins ago












Is it a part of (A,B) or part of A, I am confused
– Mehdi Souregi
13 mins ago




Is it a part of (A,B) or part of A, I am confused
– Mehdi Souregi
13 mins ago










2 Answers
2






active

oldest

votes


















1














Using the definition of $P(A|B)$ which is equal to $frac{P(Acap B)}{P(B)}$. Hence, you can't show it explicitly on the diagram as it is defined base on the division of two parts on the diagram. The value of blue part over the value of red circle. Hence it is $frac{0.1}{0.3 + 0.1} = frac{1}{4}$.






share|cite|improve this answer





























    1














    Remember that



    $$
    P(A|B) = frac{P(A, B)}{P(B)} = frac{0.1}{0.3 + 0.1} = frac{1}{4},
    $$



    which means that $P(A|B)$ is given by the proportion of the blue zone in your picture with respect to the red $B$ circle. This is not immediately visible in the diagram, so you'll have to use your imagination a bit to see the blue zone being $1/4$ of the size of the red circle.






    share|cite|improve this answer





















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      2 Answers
      2






      active

      oldest

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      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

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      1














      Using the definition of $P(A|B)$ which is equal to $frac{P(Acap B)}{P(B)}$. Hence, you can't show it explicitly on the diagram as it is defined base on the division of two parts on the diagram. The value of blue part over the value of red circle. Hence it is $frac{0.1}{0.3 + 0.1} = frac{1}{4}$.






      share|cite|improve this answer


























        1














        Using the definition of $P(A|B)$ which is equal to $frac{P(Acap B)}{P(B)}$. Hence, you can't show it explicitly on the diagram as it is defined base on the division of two parts on the diagram. The value of blue part over the value of red circle. Hence it is $frac{0.1}{0.3 + 0.1} = frac{1}{4}$.






        share|cite|improve this answer
























          1












          1








          1






          Using the definition of $P(A|B)$ which is equal to $frac{P(Acap B)}{P(B)}$. Hence, you can't show it explicitly on the diagram as it is defined base on the division of two parts on the diagram. The value of blue part over the value of red circle. Hence it is $frac{0.1}{0.3 + 0.1} = frac{1}{4}$.






          share|cite|improve this answer












          Using the definition of $P(A|B)$ which is equal to $frac{P(Acap B)}{P(B)}$. Hence, you can't show it explicitly on the diagram as it is defined base on the division of two parts on the diagram. The value of blue part over the value of red circle. Hence it is $frac{0.1}{0.3 + 0.1} = frac{1}{4}$.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered 13 mins ago









          OmG

          20128




          20128

























              1














              Remember that



              $$
              P(A|B) = frac{P(A, B)}{P(B)} = frac{0.1}{0.3 + 0.1} = frac{1}{4},
              $$



              which means that $P(A|B)$ is given by the proportion of the blue zone in your picture with respect to the red $B$ circle. This is not immediately visible in the diagram, so you'll have to use your imagination a bit to see the blue zone being $1/4$ of the size of the red circle.






              share|cite|improve this answer


























                1














                Remember that



                $$
                P(A|B) = frac{P(A, B)}{P(B)} = frac{0.1}{0.3 + 0.1} = frac{1}{4},
                $$



                which means that $P(A|B)$ is given by the proportion of the blue zone in your picture with respect to the red $B$ circle. This is not immediately visible in the diagram, so you'll have to use your imagination a bit to see the blue zone being $1/4$ of the size of the red circle.






                share|cite|improve this answer
























                  1












                  1








                  1






                  Remember that



                  $$
                  P(A|B) = frac{P(A, B)}{P(B)} = frac{0.1}{0.3 + 0.1} = frac{1}{4},
                  $$



                  which means that $P(A|B)$ is given by the proportion of the blue zone in your picture with respect to the red $B$ circle. This is not immediately visible in the diagram, so you'll have to use your imagination a bit to see the blue zone being $1/4$ of the size of the red circle.






                  share|cite|improve this answer












                  Remember that



                  $$
                  P(A|B) = frac{P(A, B)}{P(B)} = frac{0.1}{0.3 + 0.1} = frac{1}{4},
                  $$



                  which means that $P(A|B)$ is given by the proportion of the blue zone in your picture with respect to the red $B$ circle. This is not immediately visible in the diagram, so you'll have to use your imagination a bit to see the blue zone being $1/4$ of the size of the red circle.







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered 11 mins ago









                  Waldir Leoncio

                  1,36052234




                  1,36052234






















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