What is P(A/B) in Venn diagram?
I am trying to understand P(A/B) in practice. I know that (A,B) is the intersection between A and B on the diagram, and I know as well that P(A/B) is probability of A given B. But where is P(A/B) on the diagram ?
probability conditional-probability
asked 18 mins ago
Mehdi Souregi
1063
New contributor
Mehdi Souregi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I am trying to understand P(A/B) in practice. I know that (A,B) is the intersection between A and B on the diagram, and I know as well that P(A/B) is probability of A given B. But where is P(A/B) on the diagram ?
probability conditional-probability
asked 18 mins ago
Mehdi Souregi
1063
New contributor
Mehdi Souregi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
It is not on the diagram.
– Xi'an
17 mins ago
How can I represent it (on my mind) ?
– Mehdi Souregi
15 mins ago
Is it a part of (A,B) or part of A, I am confused
– Mehdi Souregi
13 mins ago
add a comment |
I am trying to understand P(A/B) in practice. I know that (A,B) is the intersection between A and B on the diagram, and I know as well that P(A/B) is probability of A given B. But where is P(A/B) on the diagram ?
probability conditional-probability
asked 18 mins ago
Mehdi Souregi
1063
New contributor
Mehdi Souregi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I am trying to understand P(A/B) in practice. I know that (A,B) is the intersection between A and B on the diagram, and I know as well that P(A/B) is probability of A given B. But where is P(A/B) on the diagram ?
probability conditional-probability
probability conditional-probability
asked 18 mins ago
Mehdi Souregi
1063
New contributor
Mehdi Souregi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 18 mins ago
Mehdi Souregi
1063
New contributor
Mehdi Souregi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 18 mins ago
Mehdi Souregi
1063
New contributor
Mehdi Souregi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 18 mins ago
Mehdi Souregi
1063
asked 18 mins ago
Mehdi Souregi
1063
1063
New contributor
Mehdi Souregi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Mehdi Souregi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Mehdi Souregi is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
It is not on the diagram.
– Xi'an
17 mins ago
How can I represent it (on my mind) ?
– Mehdi Souregi
15 mins ago
Is it a part of (A,B) or part of A, I am confused
– Mehdi Souregi
13 mins ago
add a comment |
1
It is not on the diagram.
– Xi'an
17 mins ago
How can I represent it (on my mind) ?
– Mehdi Souregi
15 mins ago
Is it a part of (A,B) or part of A, I am confused
– Mehdi Souregi
13 mins ago
1
1
It is not on the diagram.
– Xi'an
17 mins ago
It is not on the diagram.
– Xi'an
17 mins ago
How can I represent it (on my mind) ?
– Mehdi Souregi
15 mins ago
How can I represent it (on my mind) ?
– Mehdi Souregi
15 mins ago
Is it a part of (A,B) or part of A, I am confused
– Mehdi Souregi
13 mins ago
Is it a part of (A,B) or part of A, I am confused
– Mehdi Souregi
13 mins ago
add a comment |
2 Answers
2
active
oldest
votes
Using the definition of $P(A|B)$ which is equal to $frac{P(Acap B)}{P(B)}$. Hence, you can't show it explicitly on the diagram as it is defined base on the division of two parts on the diagram. The value of blue part over the value of red circle. Hence it is $frac{0.1}{0.3 + 0.1} = frac{1}{4}$.
answered 13 mins ago
OmG
20128
add a comment |
Remember that
$$
P(A|B) = frac{P(A, B)}{P(B)} = frac{0.1}{0.3 + 0.1} = frac{1}{4},
$$
which means that $P(A|B)$ is given by the proportion of the blue zone in your picture with respect to the red $B$ circle. This is not immediately visible in the diagram, so you'll have to use your imagination a bit to see the blue zone being $1/4$ of the size of the red circle.
answered 11 mins ago
Waldir Leoncio
1,36052234
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Using the definition of $P(A|B)$ which is equal to $frac{P(Acap B)}{P(B)}$. Hence, you can't show it explicitly on the diagram as it is defined base on the division of two parts on the diagram. The value of blue part over the value of red circle. Hence it is $frac{0.1}{0.3 + 0.1} = frac{1}{4}$.
answered 13 mins ago
OmG
20128
add a comment |
Using the definition of $P(A|B)$ which is equal to $frac{P(Acap B)}{P(B)}$. Hence, you can't show it explicitly on the diagram as it is defined base on the division of two parts on the diagram. The value of blue part over the value of red circle. Hence it is $frac{0.1}{0.3 + 0.1} = frac{1}{4}$.
answered 13 mins ago
OmG
20128
add a comment |
Using the definition of $P(A|B)$ which is equal to $frac{P(Acap B)}{P(B)}$. Hence, you can't show it explicitly on the diagram as it is defined base on the division of two parts on the diagram. The value of blue part over the value of red circle. Hence it is $frac{0.1}{0.3 + 0.1} = frac{1}{4}$.
answered 13 mins ago
OmG
20128
Using the definition of $P(A|B)$ which is equal to $frac{P(Acap B)}{P(B)}$. Hence, you can't show it explicitly on the diagram as it is defined base on the division of two parts on the diagram. The value of blue part over the value of red circle. Hence it is $frac{0.1}{0.3 + 0.1} = frac{1}{4}$.
answered 13 mins ago
OmG
20128
answered 13 mins ago
OmG
20128
answered 13 mins ago
OmG
20128
answered 13 mins ago
OmG
20128
20128
add a comment |
add a comment |
Remember that
$$
P(A|B) = frac{P(A, B)}{P(B)} = frac{0.1}{0.3 + 0.1} = frac{1}{4},
$$
which means that $P(A|B)$ is given by the proportion of the blue zone in your picture with respect to the red $B$ circle. This is not immediately visible in the diagram, so you'll have to use your imagination a bit to see the blue zone being $1/4$ of the size of the red circle.
answered 11 mins ago
Waldir Leoncio
1,36052234
add a comment |
Remember that
$$
P(A|B) = frac{P(A, B)}{P(B)} = frac{0.1}{0.3 + 0.1} = frac{1}{4},
$$
which means that $P(A|B)$ is given by the proportion of the blue zone in your picture with respect to the red $B$ circle. This is not immediately visible in the diagram, so you'll have to use your imagination a bit to see the blue zone being $1/4$ of the size of the red circle.
answered 11 mins ago
Waldir Leoncio
1,36052234
add a comment |
Remember that
$$
P(A|B) = frac{P(A, B)}{P(B)} = frac{0.1}{0.3 + 0.1} = frac{1}{4},
$$
which means that $P(A|B)$ is given by the proportion of the blue zone in your picture with respect to the red $B$ circle. This is not immediately visible in the diagram, so you'll have to use your imagination a bit to see the blue zone being $1/4$ of the size of the red circle.
answered 11 mins ago
Waldir Leoncio
1,36052234
Remember that
$$
P(A|B) = frac{P(A, B)}{P(B)} = frac{0.1}{0.3 + 0.1} = frac{1}{4},
$$
which means that $P(A|B)$ is given by the proportion of the blue zone in your picture with respect to the red $B$ circle. This is not immediately visible in the diagram, so you'll have to use your imagination a bit to see the blue zone being $1/4$ of the size of the red circle.
answered 11 mins ago
Waldir Leoncio
1,36052234
answered 11 mins ago
Waldir Leoncio
1,36052234
answered 11 mins ago
Waldir Leoncio
1,36052234
answered 11 mins ago
Waldir Leoncio
1,36052234
1,36052234
add a comment |
add a comment |
Mehdi Souregi is a new contributor. Be nice, and check out our Code of Conduct.
Mehdi Souregi is a new contributor. Be nice, and check out our Code of Conduct.
Mehdi Souregi is a new contributor. Be nice, and check out our Code of Conduct.
Mehdi Souregi is a new contributor. Be nice, and check out our Code of Conduct.
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1
It is not on the diagram.
– Xi'an
17 mins ago
How can I represent it (on my mind) ?
– Mehdi Souregi
15 mins ago
Is it a part of (A,B) or part of A, I am confused
– Mehdi Souregi
13 mins ago