A Very Illegal Position
It's been a while since I've done a chess puzzle, so here's one!
This position is illegal in quite a lot of ways:
It's illegal in at least 10 ways. The first one to find all of the ways this position is illegal (it's 10 or more, I know exactly how many) gets the check and +1 from me.
Good luck and happy puzzling!
chess
add a comment |
It's been a while since I've done a chess puzzle, so here's one!
This position is illegal in quite a lot of ways:
It's illegal in at least 10 ways. The first one to find all of the ways this position is illegal (it's 10 or more, I know exactly how many) gets the check and +1 from me.
Good luck and happy puzzling!
chess
i assume you mean for us to find the illegal ways and not the legal ways
– AHKieran
2 hours ago
1
@AHKieran fixed that little typo :P
– Excited Raichu
2 hours ago
add a comment |
It's been a while since I've done a chess puzzle, so here's one!
This position is illegal in quite a lot of ways:
It's illegal in at least 10 ways. The first one to find all of the ways this position is illegal (it's 10 or more, I know exactly how many) gets the check and +1 from me.
Good luck and happy puzzling!
chess
It's been a while since I've done a chess puzzle, so here's one!
This position is illegal in quite a lot of ways:
It's illegal in at least 10 ways. The first one to find all of the ways this position is illegal (it's 10 or more, I know exactly how many) gets the check and +1 from me.
Good luck and happy puzzling!
chess
chess
edited 2 hours ago
asked 2 hours ago
Excited Raichu
5,8802863
5,8802863
i assume you mean for us to find the illegal ways and not the legal ways
– AHKieran
2 hours ago
1
@AHKieran fixed that little typo :P
– Excited Raichu
2 hours ago
add a comment |
i assume you mean for us to find the illegal ways and not the legal ways
– AHKieran
2 hours ago
1
@AHKieran fixed that little typo :P
– Excited Raichu
2 hours ago
i assume you mean for us to find the illegal ways and not the legal ways
– AHKieran
2 hours ago
i assume you mean for us to find the illegal ways and not the legal ways
– AHKieran
2 hours ago
1
1
@AHKieran fixed that little typo :P
– Excited Raichu
2 hours ago
@AHKieran fixed that little typo :P
– Excited Raichu
2 hours ago
add a comment |
2 Answers
2
active
oldest
votes
1.
Both kings are in check.
2.
The black king is in check by both the Rc3 and Bg4.
3.
The white bishop on b1 can only arrive there via a2 and c2, and there are white pawns on a2 and c2 which can't have moved.
4.
Black has nine pawns.
5.
White has two light-squared bishops; one must have been promoted but White has still eight pawns.
6.
White's pawns seem to have captured three times (b-pawn to d5, d-pawn to e3), but Black's only missing piece is a single knight. Also, the f7 pawn can only get there via captures (unless the black f6 pawn somehow dropped out of thin air, see 4.)
7.
There's no way for the black rook which started on h8 to escape (to either b6 or a1).
I'm not sure I can find more; for example,
it will be hard for the Ra1 to reach that square, but once you assume the Bb1 materialized out of thin air (see 3.), it's not a problem anymore.
Also,
the black pawns are 7 columns 'away' from their home squares, but if you assume the g3 has been dropped there, only 4 captures are required to account for the a- and b-pawns, and there are four white pieces missing (two knights, a rook and the queen).
A pitfall:
the white king can be put in check this way; Black's last move could have been Nh4+ (discovered check)
Note that
some of these irregularities could happen during a game of bughouse.
rook h8 could have been captured by a white knight, though
– Bass
2 hours ago
True, but that would require another promoted black pawn.
– Glorfindel
2 hours ago
add a comment |
1. bishop in g4 in check
2. rook in c3 in check
3. bishop in f3 in check
4. rook in a1 cant get there
5. 9 black pawns
6. pawn in a3 cant get there
7. pawn in g3 cant get there
8. pawn in f7 cant get there
9. 2 white bishop on white squares
10. pawn in e3 cant get there
11. bishop in b1 cant get there
Your #4 and #12 are the same. The A3 pawn could have come from the C column by capturing twice, same goes for G3 from the D column, although since black is only missing 2 pieces, one of these must be illegal.
– Nuclear Wang
1 hour ago
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
1.
Both kings are in check.
2.
The black king is in check by both the Rc3 and Bg4.
3.
The white bishop on b1 can only arrive there via a2 and c2, and there are white pawns on a2 and c2 which can't have moved.
4.
Black has nine pawns.
5.
White has two light-squared bishops; one must have been promoted but White has still eight pawns.
6.
White's pawns seem to have captured three times (b-pawn to d5, d-pawn to e3), but Black's only missing piece is a single knight. Also, the f7 pawn can only get there via captures (unless the black f6 pawn somehow dropped out of thin air, see 4.)
7.
There's no way for the black rook which started on h8 to escape (to either b6 or a1).
I'm not sure I can find more; for example,
it will be hard for the Ra1 to reach that square, but once you assume the Bb1 materialized out of thin air (see 3.), it's not a problem anymore.
Also,
the black pawns are 7 columns 'away' from their home squares, but if you assume the g3 has been dropped there, only 4 captures are required to account for the a- and b-pawns, and there are four white pieces missing (two knights, a rook and the queen).
A pitfall:
the white king can be put in check this way; Black's last move could have been Nh4+ (discovered check)
Note that
some of these irregularities could happen during a game of bughouse.
rook h8 could have been captured by a white knight, though
– Bass
2 hours ago
True, but that would require another promoted black pawn.
– Glorfindel
2 hours ago
add a comment |
1.
Both kings are in check.
2.
The black king is in check by both the Rc3 and Bg4.
3.
The white bishop on b1 can only arrive there via a2 and c2, and there are white pawns on a2 and c2 which can't have moved.
4.
Black has nine pawns.
5.
White has two light-squared bishops; one must have been promoted but White has still eight pawns.
6.
White's pawns seem to have captured three times (b-pawn to d5, d-pawn to e3), but Black's only missing piece is a single knight. Also, the f7 pawn can only get there via captures (unless the black f6 pawn somehow dropped out of thin air, see 4.)
7.
There's no way for the black rook which started on h8 to escape (to either b6 or a1).
I'm not sure I can find more; for example,
it will be hard for the Ra1 to reach that square, but once you assume the Bb1 materialized out of thin air (see 3.), it's not a problem anymore.
Also,
the black pawns are 7 columns 'away' from their home squares, but if you assume the g3 has been dropped there, only 4 captures are required to account for the a- and b-pawns, and there are four white pieces missing (two knights, a rook and the queen).
A pitfall:
the white king can be put in check this way; Black's last move could have been Nh4+ (discovered check)
Note that
some of these irregularities could happen during a game of bughouse.
rook h8 could have been captured by a white knight, though
– Bass
2 hours ago
True, but that would require another promoted black pawn.
– Glorfindel
2 hours ago
add a comment |
1.
Both kings are in check.
2.
The black king is in check by both the Rc3 and Bg4.
3.
The white bishop on b1 can only arrive there via a2 and c2, and there are white pawns on a2 and c2 which can't have moved.
4.
Black has nine pawns.
5.
White has two light-squared bishops; one must have been promoted but White has still eight pawns.
6.
White's pawns seem to have captured three times (b-pawn to d5, d-pawn to e3), but Black's only missing piece is a single knight. Also, the f7 pawn can only get there via captures (unless the black f6 pawn somehow dropped out of thin air, see 4.)
7.
There's no way for the black rook which started on h8 to escape (to either b6 or a1).
I'm not sure I can find more; for example,
it will be hard for the Ra1 to reach that square, but once you assume the Bb1 materialized out of thin air (see 3.), it's not a problem anymore.
Also,
the black pawns are 7 columns 'away' from their home squares, but if you assume the g3 has been dropped there, only 4 captures are required to account for the a- and b-pawns, and there are four white pieces missing (two knights, a rook and the queen).
A pitfall:
the white king can be put in check this way; Black's last move could have been Nh4+ (discovered check)
Note that
some of these irregularities could happen during a game of bughouse.
1.
Both kings are in check.
2.
The black king is in check by both the Rc3 and Bg4.
3.
The white bishop on b1 can only arrive there via a2 and c2, and there are white pawns on a2 and c2 which can't have moved.
4.
Black has nine pawns.
5.
White has two light-squared bishops; one must have been promoted but White has still eight pawns.
6.
White's pawns seem to have captured three times (b-pawn to d5, d-pawn to e3), but Black's only missing piece is a single knight. Also, the f7 pawn can only get there via captures (unless the black f6 pawn somehow dropped out of thin air, see 4.)
7.
There's no way for the black rook which started on h8 to escape (to either b6 or a1).
I'm not sure I can find more; for example,
it will be hard for the Ra1 to reach that square, but once you assume the Bb1 materialized out of thin air (see 3.), it's not a problem anymore.
Also,
the black pawns are 7 columns 'away' from their home squares, but if you assume the g3 has been dropped there, only 4 captures are required to account for the a- and b-pawns, and there are four white pieces missing (two knights, a rook and the queen).
A pitfall:
the white king can be put in check this way; Black's last move could have been Nh4+ (discovered check)
Note that
some of these irregularities could happen during a game of bughouse.
edited 2 hours ago
answered 2 hours ago
Glorfindel
13.3k34982
13.3k34982
rook h8 could have been captured by a white knight, though
– Bass
2 hours ago
True, but that would require another promoted black pawn.
– Glorfindel
2 hours ago
add a comment |
rook h8 could have been captured by a white knight, though
– Bass
2 hours ago
True, but that would require another promoted black pawn.
– Glorfindel
2 hours ago
rook h8 could have been captured by a white knight, though
– Bass
2 hours ago
rook h8 could have been captured by a white knight, though
– Bass
2 hours ago
True, but that would require another promoted black pawn.
– Glorfindel
2 hours ago
True, but that would require another promoted black pawn.
– Glorfindel
2 hours ago
add a comment |
1. bishop in g4 in check
2. rook in c3 in check
3. bishop in f3 in check
4. rook in a1 cant get there
5. 9 black pawns
6. pawn in a3 cant get there
7. pawn in g3 cant get there
8. pawn in f7 cant get there
9. 2 white bishop on white squares
10. pawn in e3 cant get there
11. bishop in b1 cant get there
Your #4 and #12 are the same. The A3 pawn could have come from the C column by capturing twice, same goes for G3 from the D column, although since black is only missing 2 pieces, one of these must be illegal.
– Nuclear Wang
1 hour ago
add a comment |
1. bishop in g4 in check
2. rook in c3 in check
3. bishop in f3 in check
4. rook in a1 cant get there
5. 9 black pawns
6. pawn in a3 cant get there
7. pawn in g3 cant get there
8. pawn in f7 cant get there
9. 2 white bishop on white squares
10. pawn in e3 cant get there
11. bishop in b1 cant get there
Your #4 and #12 are the same. The A3 pawn could have come from the C column by capturing twice, same goes for G3 from the D column, although since black is only missing 2 pieces, one of these must be illegal.
– Nuclear Wang
1 hour ago
add a comment |
1. bishop in g4 in check
2. rook in c3 in check
3. bishop in f3 in check
4. rook in a1 cant get there
5. 9 black pawns
6. pawn in a3 cant get there
7. pawn in g3 cant get there
8. pawn in f7 cant get there
9. 2 white bishop on white squares
10. pawn in e3 cant get there
11. bishop in b1 cant get there
1. bishop in g4 in check
2. rook in c3 in check
3. bishop in f3 in check
4. rook in a1 cant get there
5. 9 black pawns
6. pawn in a3 cant get there
7. pawn in g3 cant get there
8. pawn in f7 cant get there
9. 2 white bishop on white squares
10. pawn in e3 cant get there
11. bishop in b1 cant get there
edited 1 hour ago
answered 2 hours ago
pirate
491115
491115
Your #4 and #12 are the same. The A3 pawn could have come from the C column by capturing twice, same goes for G3 from the D column, although since black is only missing 2 pieces, one of these must be illegal.
– Nuclear Wang
1 hour ago
add a comment |
Your #4 and #12 are the same. The A3 pawn could have come from the C column by capturing twice, same goes for G3 from the D column, although since black is only missing 2 pieces, one of these must be illegal.
– Nuclear Wang
1 hour ago
Your #4 and #12 are the same. The A3 pawn could have come from the C column by capturing twice, same goes for G3 from the D column, although since black is only missing 2 pieces, one of these must be illegal.
– Nuclear Wang
1 hour ago
Your #4 and #12 are the same. The A3 pawn could have come from the C column by capturing twice, same goes for G3 from the D column, although since black is only missing 2 pieces, one of these must be illegal.
– Nuclear Wang
1 hour ago
add a comment |
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i assume you mean for us to find the illegal ways and not the legal ways
– AHKieran
2 hours ago
1
@AHKieran fixed that little typo :P
– Excited Raichu
2 hours ago