Is the direction of the electric field relative to the magnetic field in an electromagnetic wave a...
In an electromagnetic wave.
Could the magnetic field be mirrored around the xy-plane? Is there a specific reason that the 2 fields are oriented this way? Is it just a convention?
electromagnetism waves electromagnetic-radiation polarization
New contributor
add a comment |
In an electromagnetic wave.
Could the magnetic field be mirrored around the xy-plane? Is there a specific reason that the 2 fields are oriented this way? Is it just a convention?
electromagnetism waves electromagnetic-radiation polarization
New contributor
1
Please, report the source of the picture.
– Massimo Ortolano
1 hour ago
add a comment |
In an electromagnetic wave.
Could the magnetic field be mirrored around the xy-plane? Is there a specific reason that the 2 fields are oriented this way? Is it just a convention?
electromagnetism waves electromagnetic-radiation polarization
New contributor
In an electromagnetic wave.
Could the magnetic field be mirrored around the xy-plane? Is there a specific reason that the 2 fields are oriented this way? Is it just a convention?
electromagnetism waves electromagnetic-radiation polarization
electromagnetism waves electromagnetic-radiation polarization
New contributor
New contributor
edited 1 hour ago
Qmechanic♦
101k121831151
101k121831151
New contributor
asked 2 hours ago
Alexander Ameye
312
312
New contributor
New contributor
1
Please, report the source of the picture.
– Massimo Ortolano
1 hour ago
add a comment |
1
Please, report the source of the picture.
– Massimo Ortolano
1 hour ago
1
1
Please, report the source of the picture.
– Massimo Ortolano
1 hour ago
Please, report the source of the picture.
– Massimo Ortolano
1 hour ago
add a comment |
3 Answers
3
active
oldest
votes
The direction of the fields of an electromagnetic wave is not conventional but it's determined by Maxwell's equations. For the particular case of a plane electromagnetic wave of angular frequency $omega$ in vacuum, which can be represented by the picture you posted, Maxwell's equations require that the wave vector $boldsymbol{k}$, the electric field $boldsymbol{E}$ and the magnetic flux density $boldsymbol{B}$ obey the relationships (the dot represent the scalar product and the cross the vector product)
$$begin{align}&boldsymbol{k}cdot boldsymbol{E} = 0, \ &boldsymbol{k}cdot boldsymbol{B} = 0, \ & boldsymbol{B}=frac{1}{omega}boldsymbol{k}times boldsymbol{E}.end{align}$$
This means that $boldsymbol{k}$, $boldsymbol{E}$ and $boldsymbol{B}$ are three orthogonal vectors and that the direction of any one of them is determined by the other two. Therefore, no, you cannot mirror the magnetic field in the picture.
You may want to start with "Having defined the direction of B by the Lorentz rule ... " (BTW -1 was not me).
– Bruce Greetham
1 hour ago
2
@BruceGreetham The point is that the magnetic field is defined in that way: once you have a certain definition, you cannot mirror the magnetic field (which is, I think, what the OP is asking).
– Massimo Ortolano
1 hour ago
Massimo, agree with you. But, both cases - left handed and right-handed spin - are a solution.
– HolgerFiedler
1 hour ago
Yes I think that is what OP is asking too.
– Bruce Greetham
1 hour ago
1
@HolgerFriedler This question is about a trivial redefinition of B, not about spin.
– my2cts
37 mins ago
add a comment |
If you were to flip the direction of the magnetic field in the above picture, it would describe light propagating in the opposite direction—so no, in this way, its direction is not a convention.
However, it's important to keep in mind that the direction of the magnetic field is a convention at a more fundamental level. It represents an oriented plane perpendicular to its direction via an orientation rule. If we all decided to use the "left hand rule" instead of the right hand rule for the cross product, then the magnetic field would point in the opposite direction. It is a bivector, or a pseudovector, field.
The electric field is a true vector field. At least in the three-dimensional description, which is itself a (very decent) convention, as long as we acknowledge that this picture depends on our reference frame.
In the four-dimensional picture, electric and magnetic fields can be understood as a single bivector field, such that a choice of reference frame determines a splitting of this bivector into independent "timelike" (electric) and "spacelike" (magnetic) planes.
That may be more than you were originally looking for, but I think this question makes for a good entry point to many of the other choices of representation that we make in physics.
add a comment |
Electrons in an antenna rod, accelerated in one direction, all emit photons with the same spin of their electric and magnetic field components. This is obvious, since the receiving antennas could be made of a rod to receive the changing electric field or could be made of a ring (available in the German wiki only) to receive the magnetic field. If accelerated in the same direction electrons would have spin clockwise and anti clockwise one would not be able to use the magnetic component (because both variations will cancel out each over).
I’m not sure but think that protons and positrons will have the opposite spin to electrons and antiprotons. Clarification from specialists will be nice.
1
This question is not related to spin.
– my2cts
35 mins ago
add a comment |
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3 Answers
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active
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votes
3 Answers
3
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oldest
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The direction of the fields of an electromagnetic wave is not conventional but it's determined by Maxwell's equations. For the particular case of a plane electromagnetic wave of angular frequency $omega$ in vacuum, which can be represented by the picture you posted, Maxwell's equations require that the wave vector $boldsymbol{k}$, the electric field $boldsymbol{E}$ and the magnetic flux density $boldsymbol{B}$ obey the relationships (the dot represent the scalar product and the cross the vector product)
$$begin{align}&boldsymbol{k}cdot boldsymbol{E} = 0, \ &boldsymbol{k}cdot boldsymbol{B} = 0, \ & boldsymbol{B}=frac{1}{omega}boldsymbol{k}times boldsymbol{E}.end{align}$$
This means that $boldsymbol{k}$, $boldsymbol{E}$ and $boldsymbol{B}$ are three orthogonal vectors and that the direction of any one of them is determined by the other two. Therefore, no, you cannot mirror the magnetic field in the picture.
You may want to start with "Having defined the direction of B by the Lorentz rule ... " (BTW -1 was not me).
– Bruce Greetham
1 hour ago
2
@BruceGreetham The point is that the magnetic field is defined in that way: once you have a certain definition, you cannot mirror the magnetic field (which is, I think, what the OP is asking).
– Massimo Ortolano
1 hour ago
Massimo, agree with you. But, both cases - left handed and right-handed spin - are a solution.
– HolgerFiedler
1 hour ago
Yes I think that is what OP is asking too.
– Bruce Greetham
1 hour ago
1
@HolgerFriedler This question is about a trivial redefinition of B, not about spin.
– my2cts
37 mins ago
add a comment |
The direction of the fields of an electromagnetic wave is not conventional but it's determined by Maxwell's equations. For the particular case of a plane electromagnetic wave of angular frequency $omega$ in vacuum, which can be represented by the picture you posted, Maxwell's equations require that the wave vector $boldsymbol{k}$, the electric field $boldsymbol{E}$ and the magnetic flux density $boldsymbol{B}$ obey the relationships (the dot represent the scalar product and the cross the vector product)
$$begin{align}&boldsymbol{k}cdot boldsymbol{E} = 0, \ &boldsymbol{k}cdot boldsymbol{B} = 0, \ & boldsymbol{B}=frac{1}{omega}boldsymbol{k}times boldsymbol{E}.end{align}$$
This means that $boldsymbol{k}$, $boldsymbol{E}$ and $boldsymbol{B}$ are three orthogonal vectors and that the direction of any one of them is determined by the other two. Therefore, no, you cannot mirror the magnetic field in the picture.
You may want to start with "Having defined the direction of B by the Lorentz rule ... " (BTW -1 was not me).
– Bruce Greetham
1 hour ago
2
@BruceGreetham The point is that the magnetic field is defined in that way: once you have a certain definition, you cannot mirror the magnetic field (which is, I think, what the OP is asking).
– Massimo Ortolano
1 hour ago
Massimo, agree with you. But, both cases - left handed and right-handed spin - are a solution.
– HolgerFiedler
1 hour ago
Yes I think that is what OP is asking too.
– Bruce Greetham
1 hour ago
1
@HolgerFriedler This question is about a trivial redefinition of B, not about spin.
– my2cts
37 mins ago
add a comment |
The direction of the fields of an electromagnetic wave is not conventional but it's determined by Maxwell's equations. For the particular case of a plane electromagnetic wave of angular frequency $omega$ in vacuum, which can be represented by the picture you posted, Maxwell's equations require that the wave vector $boldsymbol{k}$, the electric field $boldsymbol{E}$ and the magnetic flux density $boldsymbol{B}$ obey the relationships (the dot represent the scalar product and the cross the vector product)
$$begin{align}&boldsymbol{k}cdot boldsymbol{E} = 0, \ &boldsymbol{k}cdot boldsymbol{B} = 0, \ & boldsymbol{B}=frac{1}{omega}boldsymbol{k}times boldsymbol{E}.end{align}$$
This means that $boldsymbol{k}$, $boldsymbol{E}$ and $boldsymbol{B}$ are three orthogonal vectors and that the direction of any one of them is determined by the other two. Therefore, no, you cannot mirror the magnetic field in the picture.
The direction of the fields of an electromagnetic wave is not conventional but it's determined by Maxwell's equations. For the particular case of a plane electromagnetic wave of angular frequency $omega$ in vacuum, which can be represented by the picture you posted, Maxwell's equations require that the wave vector $boldsymbol{k}$, the electric field $boldsymbol{E}$ and the magnetic flux density $boldsymbol{B}$ obey the relationships (the dot represent the scalar product and the cross the vector product)
$$begin{align}&boldsymbol{k}cdot boldsymbol{E} = 0, \ &boldsymbol{k}cdot boldsymbol{B} = 0, \ & boldsymbol{B}=frac{1}{omega}boldsymbol{k}times boldsymbol{E}.end{align}$$
This means that $boldsymbol{k}$, $boldsymbol{E}$ and $boldsymbol{B}$ are three orthogonal vectors and that the direction of any one of them is determined by the other two. Therefore, no, you cannot mirror the magnetic field in the picture.
edited 1 hour ago
answered 1 hour ago
Massimo Ortolano
1,8751615
1,8751615
You may want to start with "Having defined the direction of B by the Lorentz rule ... " (BTW -1 was not me).
– Bruce Greetham
1 hour ago
2
@BruceGreetham The point is that the magnetic field is defined in that way: once you have a certain definition, you cannot mirror the magnetic field (which is, I think, what the OP is asking).
– Massimo Ortolano
1 hour ago
Massimo, agree with you. But, both cases - left handed and right-handed spin - are a solution.
– HolgerFiedler
1 hour ago
Yes I think that is what OP is asking too.
– Bruce Greetham
1 hour ago
1
@HolgerFriedler This question is about a trivial redefinition of B, not about spin.
– my2cts
37 mins ago
add a comment |
You may want to start with "Having defined the direction of B by the Lorentz rule ... " (BTW -1 was not me).
– Bruce Greetham
1 hour ago
2
@BruceGreetham The point is that the magnetic field is defined in that way: once you have a certain definition, you cannot mirror the magnetic field (which is, I think, what the OP is asking).
– Massimo Ortolano
1 hour ago
Massimo, agree with you. But, both cases - left handed and right-handed spin - are a solution.
– HolgerFiedler
1 hour ago
Yes I think that is what OP is asking too.
– Bruce Greetham
1 hour ago
1
@HolgerFriedler This question is about a trivial redefinition of B, not about spin.
– my2cts
37 mins ago
You may want to start with "Having defined the direction of B by the Lorentz rule ... " (BTW -1 was not me).
– Bruce Greetham
1 hour ago
You may want to start with "Having defined the direction of B by the Lorentz rule ... " (BTW -1 was not me).
– Bruce Greetham
1 hour ago
2
2
@BruceGreetham The point is that the magnetic field is defined in that way: once you have a certain definition, you cannot mirror the magnetic field (which is, I think, what the OP is asking).
– Massimo Ortolano
1 hour ago
@BruceGreetham The point is that the magnetic field is defined in that way: once you have a certain definition, you cannot mirror the magnetic field (which is, I think, what the OP is asking).
– Massimo Ortolano
1 hour ago
Massimo, agree with you. But, both cases - left handed and right-handed spin - are a solution.
– HolgerFiedler
1 hour ago
Massimo, agree with you. But, both cases - left handed and right-handed spin - are a solution.
– HolgerFiedler
1 hour ago
Yes I think that is what OP is asking too.
– Bruce Greetham
1 hour ago
Yes I think that is what OP is asking too.
– Bruce Greetham
1 hour ago
1
1
@HolgerFriedler This question is about a trivial redefinition of B, not about spin.
– my2cts
37 mins ago
@HolgerFriedler This question is about a trivial redefinition of B, not about spin.
– my2cts
37 mins ago
add a comment |
If you were to flip the direction of the magnetic field in the above picture, it would describe light propagating in the opposite direction—so no, in this way, its direction is not a convention.
However, it's important to keep in mind that the direction of the magnetic field is a convention at a more fundamental level. It represents an oriented plane perpendicular to its direction via an orientation rule. If we all decided to use the "left hand rule" instead of the right hand rule for the cross product, then the magnetic field would point in the opposite direction. It is a bivector, or a pseudovector, field.
The electric field is a true vector field. At least in the three-dimensional description, which is itself a (very decent) convention, as long as we acknowledge that this picture depends on our reference frame.
In the four-dimensional picture, electric and magnetic fields can be understood as a single bivector field, such that a choice of reference frame determines a splitting of this bivector into independent "timelike" (electric) and "spacelike" (magnetic) planes.
That may be more than you were originally looking for, but I think this question makes for a good entry point to many of the other choices of representation that we make in physics.
add a comment |
If you were to flip the direction of the magnetic field in the above picture, it would describe light propagating in the opposite direction—so no, in this way, its direction is not a convention.
However, it's important to keep in mind that the direction of the magnetic field is a convention at a more fundamental level. It represents an oriented plane perpendicular to its direction via an orientation rule. If we all decided to use the "left hand rule" instead of the right hand rule for the cross product, then the magnetic field would point in the opposite direction. It is a bivector, or a pseudovector, field.
The electric field is a true vector field. At least in the three-dimensional description, which is itself a (very decent) convention, as long as we acknowledge that this picture depends on our reference frame.
In the four-dimensional picture, electric and magnetic fields can be understood as a single bivector field, such that a choice of reference frame determines a splitting of this bivector into independent "timelike" (electric) and "spacelike" (magnetic) planes.
That may be more than you were originally looking for, but I think this question makes for a good entry point to many of the other choices of representation that we make in physics.
add a comment |
If you were to flip the direction of the magnetic field in the above picture, it would describe light propagating in the opposite direction—so no, in this way, its direction is not a convention.
However, it's important to keep in mind that the direction of the magnetic field is a convention at a more fundamental level. It represents an oriented plane perpendicular to its direction via an orientation rule. If we all decided to use the "left hand rule" instead of the right hand rule for the cross product, then the magnetic field would point in the opposite direction. It is a bivector, or a pseudovector, field.
The electric field is a true vector field. At least in the three-dimensional description, which is itself a (very decent) convention, as long as we acknowledge that this picture depends on our reference frame.
In the four-dimensional picture, electric and magnetic fields can be understood as a single bivector field, such that a choice of reference frame determines a splitting of this bivector into independent "timelike" (electric) and "spacelike" (magnetic) planes.
That may be more than you were originally looking for, but I think this question makes for a good entry point to many of the other choices of representation that we make in physics.
If you were to flip the direction of the magnetic field in the above picture, it would describe light propagating in the opposite direction—so no, in this way, its direction is not a convention.
However, it's important to keep in mind that the direction of the magnetic field is a convention at a more fundamental level. It represents an oriented plane perpendicular to its direction via an orientation rule. If we all decided to use the "left hand rule" instead of the right hand rule for the cross product, then the magnetic field would point in the opposite direction. It is a bivector, or a pseudovector, field.
The electric field is a true vector field. At least in the three-dimensional description, which is itself a (very decent) convention, as long as we acknowledge that this picture depends on our reference frame.
In the four-dimensional picture, electric and magnetic fields can be understood as a single bivector field, such that a choice of reference frame determines a splitting of this bivector into independent "timelike" (electric) and "spacelike" (magnetic) planes.
That may be more than you were originally looking for, but I think this question makes for a good entry point to many of the other choices of representation that we make in physics.
edited 23 mins ago
answered 1 hour ago
Luke Burns
284515
284515
add a comment |
add a comment |
Electrons in an antenna rod, accelerated in one direction, all emit photons with the same spin of their electric and magnetic field components. This is obvious, since the receiving antennas could be made of a rod to receive the changing electric field or could be made of a ring (available in the German wiki only) to receive the magnetic field. If accelerated in the same direction electrons would have spin clockwise and anti clockwise one would not be able to use the magnetic component (because both variations will cancel out each over).
I’m not sure but think that protons and positrons will have the opposite spin to electrons and antiprotons. Clarification from specialists will be nice.
1
This question is not related to spin.
– my2cts
35 mins ago
add a comment |
Electrons in an antenna rod, accelerated in one direction, all emit photons with the same spin of their electric and magnetic field components. This is obvious, since the receiving antennas could be made of a rod to receive the changing electric field or could be made of a ring (available in the German wiki only) to receive the magnetic field. If accelerated in the same direction electrons would have spin clockwise and anti clockwise one would not be able to use the magnetic component (because both variations will cancel out each over).
I’m not sure but think that protons and positrons will have the opposite spin to electrons and antiprotons. Clarification from specialists will be nice.
1
This question is not related to spin.
– my2cts
35 mins ago
add a comment |
Electrons in an antenna rod, accelerated in one direction, all emit photons with the same spin of their electric and magnetic field components. This is obvious, since the receiving antennas could be made of a rod to receive the changing electric field or could be made of a ring (available in the German wiki only) to receive the magnetic field. If accelerated in the same direction electrons would have spin clockwise and anti clockwise one would not be able to use the magnetic component (because both variations will cancel out each over).
I’m not sure but think that protons and positrons will have the opposite spin to electrons and antiprotons. Clarification from specialists will be nice.
Electrons in an antenna rod, accelerated in one direction, all emit photons with the same spin of their electric and magnetic field components. This is obvious, since the receiving antennas could be made of a rod to receive the changing electric field or could be made of a ring (available in the German wiki only) to receive the magnetic field. If accelerated in the same direction electrons would have spin clockwise and anti clockwise one would not be able to use the magnetic component (because both variations will cancel out each over).
I’m not sure but think that protons and positrons will have the opposite spin to electrons and antiprotons. Clarification from specialists will be nice.
answered 2 hours ago
HolgerFiedler
4,15431134
4,15431134
1
This question is not related to spin.
– my2cts
35 mins ago
add a comment |
1
This question is not related to spin.
– my2cts
35 mins ago
1
1
This question is not related to spin.
– my2cts
35 mins ago
This question is not related to spin.
– my2cts
35 mins ago
add a comment |
Alexander Ameye is a new contributor. Be nice, and check out our Code of Conduct.
Alexander Ameye is a new contributor. Be nice, and check out our Code of Conduct.
Alexander Ameye is a new contributor. Be nice, and check out our Code of Conduct.
Alexander Ameye is a new contributor. Be nice, and check out our Code of Conduct.
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Please, report the source of the picture.
– Massimo Ortolano
1 hour ago