How to plot the function the absolute value of x*(x-1)^(1/3) using tikzpicture environment
3
I am trying to plot f(x)=abs(x*(x-1)^(1/3)) on [0,2]:
I have to use tikzpicture environment but I am not able to do it in a nice way.
MWE:
documentclass{article}
usepackage[english]{babel}
usepackage[utf8]{inputenc}
usepackage[T1]{fontenc}
usepackage[a4paper,margin=1in,footskip=0.25in]{geometry}
usepackage{pgfplots}
pgfplotsset{compat=1.15}
begin{center}
begin{tikzpicture}[declare function={f(x)=ifthenelse(x>=0&&x<=1,abs(x*(x-1)^(1/3)),x*(x-1)^(1/3));}]
begin{axis}[
axis on top,
legend pos=outer north east,
axis lines = center,
xticklabel style = {font=tiny},
yticklabel style = {font=tiny},
xlabel = $x$,
ylabel = $y$,
legend style={cells={align=left}},
legend cell align={left},
]
addplot[very thick,red,samples=81,domain=0:2,name path=f] {f(x)};
end{axis}
end{tikzpicture}
end{center}
The same effect is produced if I try with addplot[very thick,red,samples=81,domain=0:2,name path=f] {abs(x*(x-1)^(1/3))};:
begin{center}
begin{tikzpicture}
begin{axis}[
axis on top,
legend pos=outer north east,
axis lines = center,
xticklabel style = {font=tiny},
yticklabel style = {font=tiny},
xlabel = $x$,
ylabel = $y$,
legend style={cells={align=left}},
legend cell align={left},
]
addplot[very thick,red,samples=81,domain=0:2,name path=f] {abs(x*(x-1)^(1/3))};
end{axis}
end{tikzpicture}
end{center}
Thanks and have a nice 2019!
tikz-pgf
asked 5 hours ago
manooooh
9071315
add a comment |
3
I am trying to plot f(x)=abs(x*(x-1)^(1/3)) on [0,2]:
I have to use tikzpicture environment but I am not able to do it in a nice way.
MWE:
documentclass{article}
usepackage[english]{babel}
usepackage[utf8]{inputenc}
usepackage[T1]{fontenc}
usepackage[a4paper,margin=1in,footskip=0.25in]{geometry}
usepackage{pgfplots}
pgfplotsset{compat=1.15}
begin{center}
begin{tikzpicture}[declare function={f(x)=ifthenelse(x>=0&&x<=1,abs(x*(x-1)^(1/3)),x*(x-1)^(1/3));}]
begin{axis}[
axis on top,
legend pos=outer north east,
axis lines = center,
xticklabel style = {font=tiny},
yticklabel style = {font=tiny},
xlabel = $x$,
ylabel = $y$,
legend style={cells={align=left}},
legend cell align={left},
]
addplot[very thick,red,samples=81,domain=0:2,name path=f] {f(x)};
end{axis}
end{tikzpicture}
end{center}
The same effect is produced if I try with addplot[very thick,red,samples=81,domain=0:2,name path=f] {abs(x*(x-1)^(1/3))};:
begin{center}
begin{tikzpicture}
begin{axis}[
axis on top,
legend pos=outer north east,
axis lines = center,
xticklabel style = {font=tiny},
yticklabel style = {font=tiny},
xlabel = $x$,
ylabel = $y$,
legend style={cells={align=left}},
legend cell align={left},
]
addplot[very thick,red,samples=81,domain=0:2,name path=f] {abs(x*(x-1)^(1/3))};
end{axis}
end{tikzpicture}
end{center}
Thanks and have a nice 2019!
tikz-pgf
asked 5 hours ago
manooooh
9071315
4
Your document is incomplete
– Christian Hupfer
5 hours ago
add a comment |
3
3
3
I am trying to plot f(x)=abs(x*(x-1)^(1/3)) on [0,2]:
I have to use tikzpicture environment but I am not able to do it in a nice way.
MWE:
documentclass{article}
usepackage[english]{babel}
usepackage[utf8]{inputenc}
usepackage[T1]{fontenc}
usepackage[a4paper,margin=1in,footskip=0.25in]{geometry}
usepackage{pgfplots}
pgfplotsset{compat=1.15}
begin{center}
begin{tikzpicture}[declare function={f(x)=ifthenelse(x>=0&&x<=1,abs(x*(x-1)^(1/3)),x*(x-1)^(1/3));}]
begin{axis}[
axis on top,
legend pos=outer north east,
axis lines = center,
xticklabel style = {font=tiny},
yticklabel style = {font=tiny},
xlabel = $x$,
ylabel = $y$,
legend style={cells={align=left}},
legend cell align={left},
]
addplot[very thick,red,samples=81,domain=0:2,name path=f] {f(x)};
end{axis}
end{tikzpicture}
end{center}
The same effect is produced if I try with addplot[very thick,red,samples=81,domain=0:2,name path=f] {abs(x*(x-1)^(1/3))};:
begin{center}
begin{tikzpicture}
begin{axis}[
axis on top,
legend pos=outer north east,
axis lines = center,
xticklabel style = {font=tiny},
yticklabel style = {font=tiny},
xlabel = $x$,
ylabel = $y$,
legend style={cells={align=left}},
legend cell align={left},
]
addplot[very thick,red,samples=81,domain=0:2,name path=f] {abs(x*(x-1)^(1/3))};
end{axis}
end{tikzpicture}
end{center}
Thanks and have a nice 2019!
tikz-pgf
asked 5 hours ago
manooooh
9071315
I am trying to plot f(x)=abs(x*(x-1)^(1/3)) on [0,2]:
I have to use tikzpicture environment but I am not able to do it in a nice way.
MWE:
documentclass{article}
usepackage[english]{babel}
usepackage[utf8]{inputenc}
usepackage[T1]{fontenc}
usepackage[a4paper,margin=1in,footskip=0.25in]{geometry}
usepackage{pgfplots}
pgfplotsset{compat=1.15}
begin{center}
begin{tikzpicture}[declare function={f(x)=ifthenelse(x>=0&&x<=1,abs(x*(x-1)^(1/3)),x*(x-1)^(1/3));}]
begin{axis}[
axis on top,
legend pos=outer north east,
axis lines = center,
xticklabel style = {font=tiny},
yticklabel style = {font=tiny},
xlabel = $x$,
ylabel = $y$,
legend style={cells={align=left}},
legend cell align={left},
]
addplot[very thick,red,samples=81,domain=0:2,name path=f] {f(x)};
end{axis}
end{tikzpicture}
end{center}
The same effect is produced if I try with addplot[very thick,red,samples=81,domain=0:2,name path=f] {abs(x*(x-1)^(1/3))};:
begin{center}
begin{tikzpicture}
begin{axis}[
axis on top,
legend pos=outer north east,
axis lines = center,
xticklabel style = {font=tiny},
yticklabel style = {font=tiny},
xlabel = $x$,
ylabel = $y$,
legend style={cells={align=left}},
legend cell align={left},
]
addplot[very thick,red,samples=81,domain=0:2,name path=f] {abs(x*(x-1)^(1/3))};
end{axis}
end{tikzpicture}
end{center}
Thanks and have a nice 2019!
tikz-pgf
tikz-pgf
asked 5 hours ago
manooooh
9071315
asked 5 hours ago
manooooh
9071315
asked 5 hours ago
manooooh
9071315
asked 5 hours ago
manooooh
9071315
asked 5 hours ago
manooooh
9071315
9071315
4
Your document is incomplete
– Christian Hupfer
5 hours ago
add a comment |
4
Your document is incomplete
– Christian Hupfer
5 hours ago
4
4
Your document is incomplete
– Christian Hupfer
5 hours ago
Your document is incomplete
– Christian Hupfer
5 hours ago
add a comment |
1 Answer
1
active
oldest
votes
6
You set the brackets in such a way that the compiler sees (x-1)^(1/3). It does not know how to plot the third root of a negative number, and let's it be. I fixed the brackets to obtain
documentclass{article}
usepackage[english]{babel}
usepackage[utf8]{inputenc}
usepackage[T1]{fontenc}
usepackage[a4paper,margin=1in,footskip=0.25in]{geometry}
usepackage{pgfplots}
pgfplotsset{compat=1.15}
usepgfplotslibrary{fillbetween}
begin{document}
begin{center}
begin{tikzpicture}[declare function={f(x)=ifthenelse(x>=0&&x<=1,x*abs(x-1)^(1/3),x*(x-1)^(1/3));}]
begin{axis}[
axis on top,
legend pos=outer north east,
axis lines = center,
xticklabel style = {font=tiny},
yticklabel style = {font=tiny},
xlabel = $x$,
ylabel = $y$,
legend style={cells={align=left}},
legend cell align={left},
]
addplot[very thick,red,samples=161,domain=0:2,name path=f] {f(x)};
end{axis}
end{tikzpicture}
end{center}
begin{center}
begin{tikzpicture}
begin{axis}[
axis on top,
legend pos=outer north east,
axis lines = center,
xticklabel style = {font=tiny},
yticklabel style = {font=tiny},
xlabel = $x$,
ylabel = $y$,
legend style={cells={align=left}},
legend cell align={left},
]
addplot[very thick,red,samples=161,domain=0:2,name path=f] {abs(x)*abs(x-1)^(1/3)};
end{axis}
end{tikzpicture}
end{center}
end{document}
Happy New Year!
answered 5 hours ago
marmot
87.5k4100188
1
Good to know! This time I did not forget the odd samples haha, Happy New Year!!
– manooooh
5 hours ago
1
@manooooh Oh, this was a real question (and not just a trick to have the first question in 2019)? ;-)
– marmot
5 hours ago
1
It is? You know I thought about it while taking a shower but for the time zones I said "There is no way it is the first question of 2019":D. If so, you are the first best answer of 2019;).
– manooooh
5 hours ago
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
6
You set the brackets in such a way that the compiler sees (x-1)^(1/3). It does not know how to plot the third root of a negative number, and let's it be. I fixed the brackets to obtain
documentclass{article}
usepackage[english]{babel}
usepackage[utf8]{inputenc}
usepackage[T1]{fontenc}
usepackage[a4paper,margin=1in,footskip=0.25in]{geometry}
usepackage{pgfplots}
pgfplotsset{compat=1.15}
usepgfplotslibrary{fillbetween}
begin{document}
begin{center}
begin{tikzpicture}[declare function={f(x)=ifthenelse(x>=0&&x<=1,x*abs(x-1)^(1/3),x*(x-1)^(1/3));}]
begin{axis}[
axis on top,
legend pos=outer north east,
axis lines = center,
xticklabel style = {font=tiny},
yticklabel style = {font=tiny},
xlabel = $x$,
ylabel = $y$,
legend style={cells={align=left}},
legend cell align={left},
]
addplot[very thick,red,samples=161,domain=0:2,name path=f] {f(x)};
end{axis}
end{tikzpicture}
end{center}
begin{center}
begin{tikzpicture}
begin{axis}[
axis on top,
legend pos=outer north east,
axis lines = center,
xticklabel style = {font=tiny},
yticklabel style = {font=tiny},
xlabel = $x$,
ylabel = $y$,
legend style={cells={align=left}},
legend cell align={left},
]
addplot[very thick,red,samples=161,domain=0:2,name path=f] {abs(x)*abs(x-1)^(1/3)};
end{axis}
end{tikzpicture}
end{center}
end{document}
Happy New Year!
answered 5 hours ago
marmot
87.5k4100188
1
Good to know! This time I did not forget the odd samples haha, Happy New Year!!
– manooooh
5 hours ago
1
@manooooh Oh, this was a real question (and not just a trick to have the first question in 2019)? ;-)
– marmot
5 hours ago
1
It is? You know I thought about it while taking a shower but for the time zones I said "There is no way it is the first question of 2019":D. If so, you are the first best answer of 2019;).
– manooooh
5 hours ago
add a comment |
6
You set the brackets in such a way that the compiler sees (x-1)^(1/3). It does not know how to plot the third root of a negative number, and let's it be. I fixed the brackets to obtain
documentclass{article}
usepackage[english]{babel}
usepackage[utf8]{inputenc}
usepackage[T1]{fontenc}
usepackage[a4paper,margin=1in,footskip=0.25in]{geometry}
usepackage{pgfplots}
pgfplotsset{compat=1.15}
usepgfplotslibrary{fillbetween}
begin{document}
begin{center}
begin{tikzpicture}[declare function={f(x)=ifthenelse(x>=0&&x<=1,x*abs(x-1)^(1/3),x*(x-1)^(1/3));}]
begin{axis}[
axis on top,
legend pos=outer north east,
axis lines = center,
xticklabel style = {font=tiny},
yticklabel style = {font=tiny},
xlabel = $x$,
ylabel = $y$,
legend style={cells={align=left}},
legend cell align={left},
]
addplot[very thick,red,samples=161,domain=0:2,name path=f] {f(x)};
end{axis}
end{tikzpicture}
end{center}
begin{center}
begin{tikzpicture}
begin{axis}[
axis on top,
legend pos=outer north east,
axis lines = center,
xticklabel style = {font=tiny},
yticklabel style = {font=tiny},
xlabel = $x$,
ylabel = $y$,
legend style={cells={align=left}},
legend cell align={left},
]
addplot[very thick,red,samples=161,domain=0:2,name path=f] {abs(x)*abs(x-1)^(1/3)};
end{axis}
end{tikzpicture}
end{center}
end{document}
Happy New Year!
answered 5 hours ago
marmot
87.5k4100188
1
Good to know! This time I did not forget the odd samples haha, Happy New Year!!
– manooooh
5 hours ago
1
@manooooh Oh, this was a real question (and not just a trick to have the first question in 2019)? ;-)
– marmot
5 hours ago
1
It is? You know I thought about it while taking a shower but for the time zones I said "There is no way it is the first question of 2019":D. If so, you are the first best answer of 2019;).
– manooooh
5 hours ago
add a comment |
6
6
6
You set the brackets in such a way that the compiler sees (x-1)^(1/3). It does not know how to plot the third root of a negative number, and let's it be. I fixed the brackets to obtain
documentclass{article}
usepackage[english]{babel}
usepackage[utf8]{inputenc}
usepackage[T1]{fontenc}
usepackage[a4paper,margin=1in,footskip=0.25in]{geometry}
usepackage{pgfplots}
pgfplotsset{compat=1.15}
usepgfplotslibrary{fillbetween}
begin{document}
begin{center}
begin{tikzpicture}[declare function={f(x)=ifthenelse(x>=0&&x<=1,x*abs(x-1)^(1/3),x*(x-1)^(1/3));}]
begin{axis}[
axis on top,
legend pos=outer north east,
axis lines = center,
xticklabel style = {font=tiny},
yticklabel style = {font=tiny},
xlabel = $x$,
ylabel = $y$,
legend style={cells={align=left}},
legend cell align={left},
]
addplot[very thick,red,samples=161,domain=0:2,name path=f] {f(x)};
end{axis}
end{tikzpicture}
end{center}
begin{center}
begin{tikzpicture}
begin{axis}[
axis on top,
legend pos=outer north east,
axis lines = center,
xticklabel style = {font=tiny},
yticklabel style = {font=tiny},
xlabel = $x$,
ylabel = $y$,
legend style={cells={align=left}},
legend cell align={left},
]
addplot[very thick,red,samples=161,domain=0:2,name path=f] {abs(x)*abs(x-1)^(1/3)};
end{axis}
end{tikzpicture}
end{center}
end{document}
Happy New Year!
answered 5 hours ago
marmot
87.5k4100188
You set the brackets in such a way that the compiler sees (x-1)^(1/3). It does not know how to plot the third root of a negative number, and let's it be. I fixed the brackets to obtain
documentclass{article}
usepackage[english]{babel}
usepackage[utf8]{inputenc}
usepackage[T1]{fontenc}
usepackage[a4paper,margin=1in,footskip=0.25in]{geometry}
usepackage{pgfplots}
pgfplotsset{compat=1.15}
usepgfplotslibrary{fillbetween}
begin{document}
begin{center}
begin{tikzpicture}[declare function={f(x)=ifthenelse(x>=0&&x<=1,x*abs(x-1)^(1/3),x*(x-1)^(1/3));}]
begin{axis}[
axis on top,
legend pos=outer north east,
axis lines = center,
xticklabel style = {font=tiny},
yticklabel style = {font=tiny},
xlabel = $x$,
ylabel = $y$,
legend style={cells={align=left}},
legend cell align={left},
]
addplot[very thick,red,samples=161,domain=0:2,name path=f] {f(x)};
end{axis}
end{tikzpicture}
end{center}
begin{center}
begin{tikzpicture}
begin{axis}[
axis on top,
legend pos=outer north east,
axis lines = center,
xticklabel style = {font=tiny},
yticklabel style = {font=tiny},
xlabel = $x$,
ylabel = $y$,
legend style={cells={align=left}},
legend cell align={left},
]
addplot[very thick,red,samples=161,domain=0:2,name path=f] {abs(x)*abs(x-1)^(1/3)};
end{axis}
end{tikzpicture}
end{center}
end{document}
Happy New Year!
answered 5 hours ago
marmot
87.5k4100188
edited 5 hours ago
answered 5 hours ago
marmot
87.5k4100188
answered 5 hours ago
marmot
87.5k4100188
answered 5 hours ago
marmot
87.5k4100188
87.5k4100188
1
Good to know! This time I did not forget the odd samples haha, Happy New Year!!
– manooooh
5 hours ago
1
@manooooh Oh, this was a real question (and not just a trick to have the first question in 2019)? ;-)
– marmot
5 hours ago
1
It is? You know I thought about it while taking a shower but for the time zones I said "There is no way it is the first question of 2019":D. If so, you are the first best answer of 2019;).
– manooooh
5 hours ago
add a comment |
1
Good to know! This time I did not forget the odd samples haha, Happy New Year!!
– manooooh
5 hours ago
1
@manooooh Oh, this was a real question (and not just a trick to have the first question in 2019)? ;-)
– marmot
5 hours ago
1
It is? You know I thought about it while taking a shower but for the time zones I said "There is no way it is the first question of 2019":D. If so, you are the first best answer of 2019;).
– manooooh
5 hours ago
1
1
Good to know! This time I did not forget the odd samples haha, Happy New Year!!
– manooooh
5 hours ago
Good to know! This time I did not forget the odd samples haha, Happy New Year!!
– manooooh
5 hours ago
1
1
@manooooh Oh, this was a real question (and not just a trick to have the first question in 2019)? ;-)
– marmot
5 hours ago
@manooooh Oh, this was a real question (and not just a trick to have the first question in 2019)? ;-)
– marmot
5 hours ago
1
1
It is? You know I thought about it while taking a shower but for the time zones I said "There is no way it is the first question of 2019"
:D. If so, you are the first best answer of 2019 ;).– manooooh
5 hours ago
It is? You know I thought about it while taking a shower but for the time zones I said "There is no way it is the first question of 2019"
:D. If so, you are the first best answer of 2019 ;).– manooooh
5 hours ago
add a comment |
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4
Your document is incomplete
– Christian Hupfer
5 hours ago