Convert string parameter to an array of one element












8














I wrote a function which has to support two types of a paramter names for a list of values. Internally it deals with the parameter as an array.



A single name is given as string and multiples names are given as an array of strings.



// simplified example
let doSome = names => names.map(name => name.toUpperCase())

names(['Bart', 'Lisa'])
// [ 'BART', 'LISA' ]
names('Homer')
// TypeError: names.map is not a function


I found a solution using Array.of() in combination with flatten() which needs some babel configuration.



doSome = names => Array.of(names).flatten().map(name => name.toUpperCase());


Is there an idiomatic way in JavaScript to get an array without a type check?










share|improve this question
























  • I think you may use split() to convert a string in to array of one element
    – Manikanta Chinta
    27 mins ago
















8














I wrote a function which has to support two types of a paramter names for a list of values. Internally it deals with the parameter as an array.



A single name is given as string and multiples names are given as an array of strings.



// simplified example
let doSome = names => names.map(name => name.toUpperCase())

names(['Bart', 'Lisa'])
// [ 'BART', 'LISA' ]
names('Homer')
// TypeError: names.map is not a function


I found a solution using Array.of() in combination with flatten() which needs some babel configuration.



doSome = names => Array.of(names).flatten().map(name => name.toUpperCase());


Is there an idiomatic way in JavaScript to get an array without a type check?










share|improve this question
























  • I think you may use split() to convert a string in to array of one element
    – Manikanta Chinta
    27 mins ago














8












8








8


0





I wrote a function which has to support two types of a paramter names for a list of values. Internally it deals with the parameter as an array.



A single name is given as string and multiples names are given as an array of strings.



// simplified example
let doSome = names => names.map(name => name.toUpperCase())

names(['Bart', 'Lisa'])
// [ 'BART', 'LISA' ]
names('Homer')
// TypeError: names.map is not a function


I found a solution using Array.of() in combination with flatten() which needs some babel configuration.



doSome = names => Array.of(names).flatten().map(name => name.toUpperCase());


Is there an idiomatic way in JavaScript to get an array without a type check?










share|improve this question















I wrote a function which has to support two types of a paramter names for a list of values. Internally it deals with the parameter as an array.



A single name is given as string and multiples names are given as an array of strings.



// simplified example
let doSome = names => names.map(name => name.toUpperCase())

names(['Bart', 'Lisa'])
// [ 'BART', 'LISA' ]
names('Homer')
// TypeError: names.map is not a function


I found a solution using Array.of() in combination with flatten() which needs some babel configuration.



doSome = names => Array.of(names).flatten().map(name => name.toUpperCase());


Is there an idiomatic way in JavaScript to get an array without a type check?







javascript arrays string






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 31 mins ago

























asked 52 mins ago









sschmeck

3,0741936




3,0741936












  • I think you may use split() to convert a string in to array of one element
    – Manikanta Chinta
    27 mins ago


















  • I think you may use split() to convert a string in to array of one element
    – Manikanta Chinta
    27 mins ago
















I think you may use split() to convert a string in to array of one element
– Manikanta Chinta
27 mins ago




I think you may use split() to convert a string in to array of one element
– Manikanta Chinta
27 mins ago












2 Answers
2






active

oldest

votes


















13














You can use Array.concat(), since concat accepts both arrays and non arrays:






const names = (v) => .concat(v).map(name => name.toUpperCase())

console.log(names(['Bart', 'Lisa'])) // [ 'BART', 'LISA' ]
console.log(names('Homer')) // ['HOMER']








share|improve this answer





























    0














    Maybe an maybe upcomming method of Array#flat would help in this case (works actually only in Chrome and FF).






    const names = unknown => [unknown].flat().map(name => name.toUpperCase())

    console.log(names(['Bart', 'Lisa']));
    console.log(names('Homer'));








    share|improve this answer





















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      2 Answers
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      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      13














      You can use Array.concat(), since concat accepts both arrays and non arrays:






      const names = (v) => .concat(v).map(name => name.toUpperCase())

      console.log(names(['Bart', 'Lisa'])) // [ 'BART', 'LISA' ]
      console.log(names('Homer')) // ['HOMER']








      share|improve this answer


























        13














        You can use Array.concat(), since concat accepts both arrays and non arrays:






        const names = (v) => .concat(v).map(name => name.toUpperCase())

        console.log(names(['Bart', 'Lisa'])) // [ 'BART', 'LISA' ]
        console.log(names('Homer')) // ['HOMER']








        share|improve this answer
























          13












          13








          13






          You can use Array.concat(), since concat accepts both arrays and non arrays:






          const names = (v) => .concat(v).map(name => name.toUpperCase())

          console.log(names(['Bart', 'Lisa'])) // [ 'BART', 'LISA' ]
          console.log(names('Homer')) // ['HOMER']








          share|improve this answer












          You can use Array.concat(), since concat accepts both arrays and non arrays:






          const names = (v) => .concat(v).map(name => name.toUpperCase())

          console.log(names(['Bart', 'Lisa'])) // [ 'BART', 'LISA' ]
          console.log(names('Homer')) // ['HOMER']








          const names = (v) => .concat(v).map(name => name.toUpperCase())

          console.log(names(['Bart', 'Lisa'])) // [ 'BART', 'LISA' ]
          console.log(names('Homer')) // ['HOMER']





          const names = (v) => .concat(v).map(name => name.toUpperCase())

          console.log(names(['Bart', 'Lisa'])) // [ 'BART', 'LISA' ]
          console.log(names('Homer')) // ['HOMER']






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 50 mins ago









          Ori Drori

          74k127792




          74k127792

























              0














              Maybe an maybe upcomming method of Array#flat would help in this case (works actually only in Chrome and FF).






              const names = unknown => [unknown].flat().map(name => name.toUpperCase())

              console.log(names(['Bart', 'Lisa']));
              console.log(names('Homer'));








              share|improve this answer


























                0














                Maybe an maybe upcomming method of Array#flat would help in this case (works actually only in Chrome and FF).






                const names = unknown => [unknown].flat().map(name => name.toUpperCase())

                console.log(names(['Bart', 'Lisa']));
                console.log(names('Homer'));








                share|improve this answer
























                  0












                  0








                  0






                  Maybe an maybe upcomming method of Array#flat would help in this case (works actually only in Chrome and FF).






                  const names = unknown => [unknown].flat().map(name => name.toUpperCase())

                  console.log(names(['Bart', 'Lisa']));
                  console.log(names('Homer'));








                  share|improve this answer












                  Maybe an maybe upcomming method of Array#flat would help in this case (works actually only in Chrome and FF).






                  const names = unknown => [unknown].flat().map(name => name.toUpperCase())

                  console.log(names(['Bart', 'Lisa']));
                  console.log(names('Homer'));








                  const names = unknown => [unknown].flat().map(name => name.toUpperCase())

                  console.log(names(['Bart', 'Lisa']));
                  console.log(names('Homer'));





                  const names = unknown => [unknown].flat().map(name => name.toUpperCase())

                  console.log(names(['Bart', 'Lisa']));
                  console.log(names('Homer'));






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 35 mins ago









                  Nina Scholz

                  176k1390155




                  176k1390155






























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