Interpreting autocorrelation in time series residuals





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I am trying to fit an ARIMA model to the following data minus the last 12 datapoints: http://users.stat.umn.edu/~kb/classes/5932/data/beer.txt



The first thing I did was take the log-difference to get a stationary process:



beer_ts <- bshort %>%pull(Amount) %>%ts(.,frequency=1)
beer_log <- log(beer_ts)
beer_adj <- diff(beer_log, differences=1)


.
.



Both the ADF & KPSS tests indicates that beer_adj is indeed stationary, which matches my visual inspection:
enter image description here
.
.



Fitting a model yields the following:



beer_arima <- auto.arima(beer_adj, seasonal=FALSE, stepwise=FALSE, approximation=FALSE)
summary(beer_arima)

Series: beer_adj
ARIMA(4,0,1) with non-zero mean

Coefficients:
ar1 ar2 ar3 ar4 ma1 mean
0.4655 0.0537 0.0512 -0.3486 -0.9360 0.0017
s.e. 0.0470 0.0517 0.0516 0.0469 0.0126 0.0005

sigma^2 estimated as 0.01282: log likelihood=312.39
AIC=-610.77 AICc=-610.5 BIC=-582.68

Training set error measures:
ME RMSE MAE MPE MAPE MASE ACF1
Training set -0.0004487926 0.1124111 0.08945575 134.5103 234.3433 0.529803 -0.06818126


.
.



When inspecting the residuals, however, they seem to be serially autocorrelated at lag 12:
enter image description here



I am unsure how I am supposed to interpret this last plot - at this stage I would have expected white noise residuals. I am new to time series analysis, but it seems to me that I am missing some fundamental step in my modelling here. Any pointers would be greatly appreciated!










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    up vote
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    I am trying to fit an ARIMA model to the following data minus the last 12 datapoints: http://users.stat.umn.edu/~kb/classes/5932/data/beer.txt



    The first thing I did was take the log-difference to get a stationary process:



    beer_ts <- bshort %>%pull(Amount) %>%ts(.,frequency=1)
    beer_log <- log(beer_ts)
    beer_adj <- diff(beer_log, differences=1)


    .
    .



    Both the ADF & KPSS tests indicates that beer_adj is indeed stationary, which matches my visual inspection:
    enter image description here
    .
    .



    Fitting a model yields the following:



    beer_arima <- auto.arima(beer_adj, seasonal=FALSE, stepwise=FALSE, approximation=FALSE)
    summary(beer_arima)

    Series: beer_adj
    ARIMA(4,0,1) with non-zero mean

    Coefficients:
    ar1 ar2 ar3 ar4 ma1 mean
    0.4655 0.0537 0.0512 -0.3486 -0.9360 0.0017
    s.e. 0.0470 0.0517 0.0516 0.0469 0.0126 0.0005

    sigma^2 estimated as 0.01282: log likelihood=312.39
    AIC=-610.77 AICc=-610.5 BIC=-582.68

    Training set error measures:
    ME RMSE MAE MPE MAPE MASE ACF1
    Training set -0.0004487926 0.1124111 0.08945575 134.5103 234.3433 0.529803 -0.06818126


    .
    .



    When inspecting the residuals, however, they seem to be serially autocorrelated at lag 12:
    enter image description here



    I am unsure how I am supposed to interpret this last plot - at this stage I would have expected white noise residuals. I am new to time series analysis, but it seems to me that I am missing some fundamental step in my modelling here. Any pointers would be greatly appreciated!










    share|cite|improve this question









    New contributor




    Student_514 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      up vote
      4
      down vote

      favorite
      1









      up vote
      4
      down vote

      favorite
      1






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      I am trying to fit an ARIMA model to the following data minus the last 12 datapoints: http://users.stat.umn.edu/~kb/classes/5932/data/beer.txt



      The first thing I did was take the log-difference to get a stationary process:



      beer_ts <- bshort %>%pull(Amount) %>%ts(.,frequency=1)
      beer_log <- log(beer_ts)
      beer_adj <- diff(beer_log, differences=1)


      .
      .



      Both the ADF & KPSS tests indicates that beer_adj is indeed stationary, which matches my visual inspection:
      enter image description here
      .
      .



      Fitting a model yields the following:



      beer_arima <- auto.arima(beer_adj, seasonal=FALSE, stepwise=FALSE, approximation=FALSE)
      summary(beer_arima)

      Series: beer_adj
      ARIMA(4,0,1) with non-zero mean

      Coefficients:
      ar1 ar2 ar3 ar4 ma1 mean
      0.4655 0.0537 0.0512 -0.3486 -0.9360 0.0017
      s.e. 0.0470 0.0517 0.0516 0.0469 0.0126 0.0005

      sigma^2 estimated as 0.01282: log likelihood=312.39
      AIC=-610.77 AICc=-610.5 BIC=-582.68

      Training set error measures:
      ME RMSE MAE MPE MAPE MASE ACF1
      Training set -0.0004487926 0.1124111 0.08945575 134.5103 234.3433 0.529803 -0.06818126


      .
      .



      When inspecting the residuals, however, they seem to be serially autocorrelated at lag 12:
      enter image description here



      I am unsure how I am supposed to interpret this last plot - at this stage I would have expected white noise residuals. I am new to time series analysis, but it seems to me that I am missing some fundamental step in my modelling here. Any pointers would be greatly appreciated!










      share|cite|improve this question









      New contributor




      Student_514 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      I am trying to fit an ARIMA model to the following data minus the last 12 datapoints: http://users.stat.umn.edu/~kb/classes/5932/data/beer.txt



      The first thing I did was take the log-difference to get a stationary process:



      beer_ts <- bshort %>%pull(Amount) %>%ts(.,frequency=1)
      beer_log <- log(beer_ts)
      beer_adj <- diff(beer_log, differences=1)


      .
      .



      Both the ADF & KPSS tests indicates that beer_adj is indeed stationary, which matches my visual inspection:
      enter image description here
      .
      .



      Fitting a model yields the following:



      beer_arima <- auto.arima(beer_adj, seasonal=FALSE, stepwise=FALSE, approximation=FALSE)
      summary(beer_arima)

      Series: beer_adj
      ARIMA(4,0,1) with non-zero mean

      Coefficients:
      ar1 ar2 ar3 ar4 ma1 mean
      0.4655 0.0537 0.0512 -0.3486 -0.9360 0.0017
      s.e. 0.0470 0.0517 0.0516 0.0469 0.0126 0.0005

      sigma^2 estimated as 0.01282: log likelihood=312.39
      AIC=-610.77 AICc=-610.5 BIC=-582.68

      Training set error measures:
      ME RMSE MAE MPE MAPE MASE ACF1
      Training set -0.0004487926 0.1124111 0.08945575 134.5103 234.3433 0.529803 -0.06818126


      .
      .



      When inspecting the residuals, however, they seem to be serially autocorrelated at lag 12:
      enter image description here



      I am unsure how I am supposed to interpret this last plot - at this stage I would have expected white noise residuals. I am new to time series analysis, but it seems to me that I am missing some fundamental step in my modelling here. Any pointers would be greatly appreciated!







      time-series arima autocorrelation residuals






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      edited 7 hours ago





















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      Check out our Code of Conduct.






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          3 Answers
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          up vote
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          You are looking at data for monthly beer production. It has seasonality that you must account for and it is this seasonality that you are noticing in your ACF plot. Note that you have 2 strands of seasonality - every 12 months (in the plot note the ACF being particularly high at 12 months and 24 months) and every 6*k (where k is odd) months (in the plot note the ACF being high at 6 months and 18 months).



          As the next steps:
          - (1) Try adding lag12 into your model to account for the seasonality every 12 months, the strongest one you observe in the ACF plot
          - (2) If after step (1), you still have serial correlation, add both lag12 and lag6 into you model; this should take care of it






          share|cite|improve this answer




























            up vote
            2
            down vote













            If I am not mistaken, the observations in this beer time series were collected 12 times a year for each year represented in the data, so the frequency of the time series is 12.



            As explained at https://www.statmethods.net/advstats/timeseries.html, for instance, frequency is the number of observations per unit time. This means that frequency = 1 for data collected once a year, frequency = 4 for data collected 4 times a year (i.e., quarterly data) and frequency = 12 for data collected 12 times a year (i.e., monthly data). Not sure why you would use frequency = 1 instead of frequency = 12 for this time series?



            For time series data where frequency = 4 or 12, you should be concerned about the possibility of seasonality (see https://anomaly.io/seasonal-trend-decomposition-in-r/).



            If seasonality is present, you should incorporate this into your time series modelling and forecasting, in which case you would use seasonal = TRUE in your auto.arima() function call.



            Before you construct the ACF and PACF plots, you can diagnose the presence of seasonality of a quarterly or monthly time series using functions such as ggseasonplot() and ggsubseriesplot() in the forecast package in R, as seen here: https://otexts.org/fpp2/seasonal-plots.html.






            share|cite|improve this answer






























              up vote
              0
              down vote













              You say "log-difference to get a stationary process" . One doesn't take logs to make the series stationary When (and why) should you take the log of a distribution (of numbers)? , one takes logs when the expected value of a model is proportional to the error variance. Note that this is not the variance of the original series ..although some textbooks and statisticians make this mistake.



              It is true that there appears to be "larger variablilty" at higher levels BUT it is more true that the error variance of a useful model changes deterministically at two points in time . Following http://docplayer.net/12080848-Outliers-level-shifts-and-variance-changes-in-time-series.html we find that enter image description here



              The final useful model accounting for a needed difference and a needed Weighted Estimation (via the identified break points in error ) and ARMA structure and adjustments made for anomalous data points is here .enter image description here



              Also note that while seasonal arima structure can be useful (as in this case ) possibilities exist for certain months of the year to have assignable cause i.e. fixed effects. This is true in this case as months (1,6 and 10) have significant deterministic impacts ... Jan & June are higher while October is significantly lower.



              The residual acf suggests sufficiency ( note that with 422 values the standard deviation of the acf roughly is 1/sqrt(422) yielding many false positives enter image description here . The plot of the residuals suggest sufficiency enter image description here . The forecast graph for the next 12 values is here enter image description here






              share|cite|improve this answer























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                3 Answers
                3






                active

                oldest

                votes








                3 Answers
                3






                active

                oldest

                votes









                active

                oldest

                votes






                active

                oldest

                votes








                up vote
                5
                down vote













                You are looking at data for monthly beer production. It has seasonality that you must account for and it is this seasonality that you are noticing in your ACF plot. Note that you have 2 strands of seasonality - every 12 months (in the plot note the ACF being particularly high at 12 months and 24 months) and every 6*k (where k is odd) months (in the plot note the ACF being high at 6 months and 18 months).



                As the next steps:
                - (1) Try adding lag12 into your model to account for the seasonality every 12 months, the strongest one you observe in the ACF plot
                - (2) If after step (1), you still have serial correlation, add both lag12 and lag6 into you model; this should take care of it






                share|cite|improve this answer

























                  up vote
                  5
                  down vote













                  You are looking at data for monthly beer production. It has seasonality that you must account for and it is this seasonality that you are noticing in your ACF plot. Note that you have 2 strands of seasonality - every 12 months (in the plot note the ACF being particularly high at 12 months and 24 months) and every 6*k (where k is odd) months (in the plot note the ACF being high at 6 months and 18 months).



                  As the next steps:
                  - (1) Try adding lag12 into your model to account for the seasonality every 12 months, the strongest one you observe in the ACF plot
                  - (2) If after step (1), you still have serial correlation, add both lag12 and lag6 into you model; this should take care of it






                  share|cite|improve this answer























                    up vote
                    5
                    down vote










                    up vote
                    5
                    down vote









                    You are looking at data for monthly beer production. It has seasonality that you must account for and it is this seasonality that you are noticing in your ACF plot. Note that you have 2 strands of seasonality - every 12 months (in the plot note the ACF being particularly high at 12 months and 24 months) and every 6*k (where k is odd) months (in the plot note the ACF being high at 6 months and 18 months).



                    As the next steps:
                    - (1) Try adding lag12 into your model to account for the seasonality every 12 months, the strongest one you observe in the ACF plot
                    - (2) If after step (1), you still have serial correlation, add both lag12 and lag6 into you model; this should take care of it






                    share|cite|improve this answer












                    You are looking at data for monthly beer production. It has seasonality that you must account for and it is this seasonality that you are noticing in your ACF plot. Note that you have 2 strands of seasonality - every 12 months (in the plot note the ACF being particularly high at 12 months and 24 months) and every 6*k (where k is odd) months (in the plot note the ACF being high at 6 months and 18 months).



                    As the next steps:
                    - (1) Try adding lag12 into your model to account for the seasonality every 12 months, the strongest one you observe in the ACF plot
                    - (2) If after step (1), you still have serial correlation, add both lag12 and lag6 into you model; this should take care of it







                    share|cite|improve this answer












                    share|cite|improve this answer



                    share|cite|improve this answer










                    answered 7 hours ago









                    ColorStatistics

                    3777




                    3777
























                        up vote
                        2
                        down vote













                        If I am not mistaken, the observations in this beer time series were collected 12 times a year for each year represented in the data, so the frequency of the time series is 12.



                        As explained at https://www.statmethods.net/advstats/timeseries.html, for instance, frequency is the number of observations per unit time. This means that frequency = 1 for data collected once a year, frequency = 4 for data collected 4 times a year (i.e., quarterly data) and frequency = 12 for data collected 12 times a year (i.e., monthly data). Not sure why you would use frequency = 1 instead of frequency = 12 for this time series?



                        For time series data where frequency = 4 or 12, you should be concerned about the possibility of seasonality (see https://anomaly.io/seasonal-trend-decomposition-in-r/).



                        If seasonality is present, you should incorporate this into your time series modelling and forecasting, in which case you would use seasonal = TRUE in your auto.arima() function call.



                        Before you construct the ACF and PACF plots, you can diagnose the presence of seasonality of a quarterly or monthly time series using functions such as ggseasonplot() and ggsubseriesplot() in the forecast package in R, as seen here: https://otexts.org/fpp2/seasonal-plots.html.






                        share|cite|improve this answer



























                          up vote
                          2
                          down vote













                          If I am not mistaken, the observations in this beer time series were collected 12 times a year for each year represented in the data, so the frequency of the time series is 12.



                          As explained at https://www.statmethods.net/advstats/timeseries.html, for instance, frequency is the number of observations per unit time. This means that frequency = 1 for data collected once a year, frequency = 4 for data collected 4 times a year (i.e., quarterly data) and frequency = 12 for data collected 12 times a year (i.e., monthly data). Not sure why you would use frequency = 1 instead of frequency = 12 for this time series?



                          For time series data where frequency = 4 or 12, you should be concerned about the possibility of seasonality (see https://anomaly.io/seasonal-trend-decomposition-in-r/).



                          If seasonality is present, you should incorporate this into your time series modelling and forecasting, in which case you would use seasonal = TRUE in your auto.arima() function call.



                          Before you construct the ACF and PACF plots, you can diagnose the presence of seasonality of a quarterly or monthly time series using functions such as ggseasonplot() and ggsubseriesplot() in the forecast package in R, as seen here: https://otexts.org/fpp2/seasonal-plots.html.






                          share|cite|improve this answer

























                            up vote
                            2
                            down vote










                            up vote
                            2
                            down vote









                            If I am not mistaken, the observations in this beer time series were collected 12 times a year for each year represented in the data, so the frequency of the time series is 12.



                            As explained at https://www.statmethods.net/advstats/timeseries.html, for instance, frequency is the number of observations per unit time. This means that frequency = 1 for data collected once a year, frequency = 4 for data collected 4 times a year (i.e., quarterly data) and frequency = 12 for data collected 12 times a year (i.e., monthly data). Not sure why you would use frequency = 1 instead of frequency = 12 for this time series?



                            For time series data where frequency = 4 or 12, you should be concerned about the possibility of seasonality (see https://anomaly.io/seasonal-trend-decomposition-in-r/).



                            If seasonality is present, you should incorporate this into your time series modelling and forecasting, in which case you would use seasonal = TRUE in your auto.arima() function call.



                            Before you construct the ACF and PACF plots, you can diagnose the presence of seasonality of a quarterly or monthly time series using functions such as ggseasonplot() and ggsubseriesplot() in the forecast package in R, as seen here: https://otexts.org/fpp2/seasonal-plots.html.






                            share|cite|improve this answer














                            If I am not mistaken, the observations in this beer time series were collected 12 times a year for each year represented in the data, so the frequency of the time series is 12.



                            As explained at https://www.statmethods.net/advstats/timeseries.html, for instance, frequency is the number of observations per unit time. This means that frequency = 1 for data collected once a year, frequency = 4 for data collected 4 times a year (i.e., quarterly data) and frequency = 12 for data collected 12 times a year (i.e., monthly data). Not sure why you would use frequency = 1 instead of frequency = 12 for this time series?



                            For time series data where frequency = 4 or 12, you should be concerned about the possibility of seasonality (see https://anomaly.io/seasonal-trend-decomposition-in-r/).



                            If seasonality is present, you should incorporate this into your time series modelling and forecasting, in which case you would use seasonal = TRUE in your auto.arima() function call.



                            Before you construct the ACF and PACF plots, you can diagnose the presence of seasonality of a quarterly or monthly time series using functions such as ggseasonplot() and ggsubseriesplot() in the forecast package in R, as seen here: https://otexts.org/fpp2/seasonal-plots.html.







                            share|cite|improve this answer














                            share|cite|improve this answer



                            share|cite|improve this answer








                            edited 7 hours ago

























                            answered 7 hours ago









                            Isabella Ghement

                            5,419319




                            5,419319






















                                up vote
                                0
                                down vote













                                You say "log-difference to get a stationary process" . One doesn't take logs to make the series stationary When (and why) should you take the log of a distribution (of numbers)? , one takes logs when the expected value of a model is proportional to the error variance. Note that this is not the variance of the original series ..although some textbooks and statisticians make this mistake.



                                It is true that there appears to be "larger variablilty" at higher levels BUT it is more true that the error variance of a useful model changes deterministically at two points in time . Following http://docplayer.net/12080848-Outliers-level-shifts-and-variance-changes-in-time-series.html we find that enter image description here



                                The final useful model accounting for a needed difference and a needed Weighted Estimation (via the identified break points in error ) and ARMA structure and adjustments made for anomalous data points is here .enter image description here



                                Also note that while seasonal arima structure can be useful (as in this case ) possibilities exist for certain months of the year to have assignable cause i.e. fixed effects. This is true in this case as months (1,6 and 10) have significant deterministic impacts ... Jan & June are higher while October is significantly lower.



                                The residual acf suggests sufficiency ( note that with 422 values the standard deviation of the acf roughly is 1/sqrt(422) yielding many false positives enter image description here . The plot of the residuals suggest sufficiency enter image description here . The forecast graph for the next 12 values is here enter image description here






                                share|cite|improve this answer



























                                  up vote
                                  0
                                  down vote













                                  You say "log-difference to get a stationary process" . One doesn't take logs to make the series stationary When (and why) should you take the log of a distribution (of numbers)? , one takes logs when the expected value of a model is proportional to the error variance. Note that this is not the variance of the original series ..although some textbooks and statisticians make this mistake.



                                  It is true that there appears to be "larger variablilty" at higher levels BUT it is more true that the error variance of a useful model changes deterministically at two points in time . Following http://docplayer.net/12080848-Outliers-level-shifts-and-variance-changes-in-time-series.html we find that enter image description here



                                  The final useful model accounting for a needed difference and a needed Weighted Estimation (via the identified break points in error ) and ARMA structure and adjustments made for anomalous data points is here .enter image description here



                                  Also note that while seasonal arima structure can be useful (as in this case ) possibilities exist for certain months of the year to have assignable cause i.e. fixed effects. This is true in this case as months (1,6 and 10) have significant deterministic impacts ... Jan & June are higher while October is significantly lower.



                                  The residual acf suggests sufficiency ( note that with 422 values the standard deviation of the acf roughly is 1/sqrt(422) yielding many false positives enter image description here . The plot of the residuals suggest sufficiency enter image description here . The forecast graph for the next 12 values is here enter image description here






                                  share|cite|improve this answer

























                                    up vote
                                    0
                                    down vote










                                    up vote
                                    0
                                    down vote









                                    You say "log-difference to get a stationary process" . One doesn't take logs to make the series stationary When (and why) should you take the log of a distribution (of numbers)? , one takes logs when the expected value of a model is proportional to the error variance. Note that this is not the variance of the original series ..although some textbooks and statisticians make this mistake.



                                    It is true that there appears to be "larger variablilty" at higher levels BUT it is more true that the error variance of a useful model changes deterministically at two points in time . Following http://docplayer.net/12080848-Outliers-level-shifts-and-variance-changes-in-time-series.html we find that enter image description here



                                    The final useful model accounting for a needed difference and a needed Weighted Estimation (via the identified break points in error ) and ARMA structure and adjustments made for anomalous data points is here .enter image description here



                                    Also note that while seasonal arima structure can be useful (as in this case ) possibilities exist for certain months of the year to have assignable cause i.e. fixed effects. This is true in this case as months (1,6 and 10) have significant deterministic impacts ... Jan & June are higher while October is significantly lower.



                                    The residual acf suggests sufficiency ( note that with 422 values the standard deviation of the acf roughly is 1/sqrt(422) yielding many false positives enter image description here . The plot of the residuals suggest sufficiency enter image description here . The forecast graph for the next 12 values is here enter image description here






                                    share|cite|improve this answer














                                    You say "log-difference to get a stationary process" . One doesn't take logs to make the series stationary When (and why) should you take the log of a distribution (of numbers)? , one takes logs when the expected value of a model is proportional to the error variance. Note that this is not the variance of the original series ..although some textbooks and statisticians make this mistake.



                                    It is true that there appears to be "larger variablilty" at higher levels BUT it is more true that the error variance of a useful model changes deterministically at two points in time . Following http://docplayer.net/12080848-Outliers-level-shifts-and-variance-changes-in-time-series.html we find that enter image description here



                                    The final useful model accounting for a needed difference and a needed Weighted Estimation (via the identified break points in error ) and ARMA structure and adjustments made for anomalous data points is here .enter image description here



                                    Also note that while seasonal arima structure can be useful (as in this case ) possibilities exist for certain months of the year to have assignable cause i.e. fixed effects. This is true in this case as months (1,6 and 10) have significant deterministic impacts ... Jan & June are higher while October is significantly lower.



                                    The residual acf suggests sufficiency ( note that with 422 values the standard deviation of the acf roughly is 1/sqrt(422) yielding many false positives enter image description here . The plot of the residuals suggest sufficiency enter image description here . The forecast graph for the next 12 values is here enter image description here







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                                    IrishStat

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